Search results
Results from the WOW.Com Content Network
In .NET, both Math.Floor () and Math.Truncate () are mathematical functions used to round down a decimal number to the nearest integer. However, there is a subtle difference between the two: 1: Math.Floor (): Math.Floor () always rounds down the decimal number to the nearest integer towards negative infinity. It returns the largest integer less ...
Math.floor will give a whole number and gets rid of the decimals. Math.random returns a number between 0 and 1 and therefore will produce decimal numbers when multiplied with 256. Thats why you want to use floor to get rid of the decimals otherwise the rgb values won't work.
Math.floor(0.9); Math.floor always rounds to the nearest whole number that is smaller than your input. You might confuse it with Math.round, that rounds to nearest whole number. This is why this code always outputs 1 or 0, since input never gets to 2 or bigger: Math.floor(Math.random()*2)
will give you a random number in the range of [min, max] because Math.random () gives you [0, 1). Let's use Math.round instead of Math.floor, Math.random () gives you [0, 1) and if you multiply it by 10, you will get [0, 10). This is a floating point and if you round it up, you will get [0, 10] as integer.
I have found two ways of taking floors in Python: 3.1415 // 1. and. import math. math.floor(3.1415) The problem with the first approach is that it return a float (namely 3.0). The second approach feels clumsy and too long.
>>> import math >>> math.floor(-3.5) -4 >>> int(-3.5) -3 Rounding down on negative numbers means that they move away from 0, truncating moves them closer to 0. Putting it differently, the floor() is always going to be lower or equal to the original. int() is going to be closer to zero or equal.
Which as far as I understood was one of the many shortcuts to floor a value in JavaScript (like ~~, and >> 0, etc). However, I was looking at a piece of code recently that did this: var val = Math.floor(myvar/ myothervar)|0; They used Math.floor() and then also did a bitwise OR with 0. The author did this many times, so it wasn't just a typo ...
The double data-type has a 53 bit mantissa. Among other things that means that a double can represent all whole up to 2^53 without precision loss. If you store such a large number in an integer you will get an overflow. Integers only have 32 bits. Returning the integer as a double is the right thing to do here because it offers a much wider ...
The Math.Floor has to account for a lot of different scenarios of handling different types. Could they have made different scenarios faster by taking short cuts as you described? Maybe they could, but that might have broken other scenarios. Just because something on the surface looks small, doesn't mean that there isn't an iceberg underneath.
4. Math.random() generates a random number between 0 and 1. Therefore Math.random()*10 generates a random number between 0 and 10, and (Math.random()*10)+1 a number between 1 and 11. Math.floor() drops the decimal of this number, and makes it an integer from 0 to 10. You can see a sequential progression of the logic here.