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For every fraction p / q (in its lowest terms) there is a Ford circle C[ p / q ], which is the circle with radius 1/(2q 2) and centre at ( p / q , 1 / 2q 2 ). Two Ford circles for different fractions are either disjoint or they are tangent to one another—two Ford circles never intersect. If 0 < p / q < 1 ...
Word search. A word search, word find, word seek, word sleuth or mystery word puzzle is a word game that consists of the letters of words placed in a grid, which usually has a rectangular or square shape. The objective of this puzzle is to find and mark all the words hidden inside the box. The words may be placed horizontally, vertically, or ...
The Department of Fun is dedicated to providing the community of Wikipedians, both young and old editors, with things to make them stay at Wikipedia, indirectly improving the encyclopedia. Below, you can find a fun and simple game to play. Please, if you have ideas for activities or competitions, do not hesitate to post them to the discussion ...
A bow compass capable of drawing the smallest possible circles. A compass, also commonly known as a pair of compasses, is a technical drawing instrument that can be used for inscribing circles or arcs. As dividers, it can also be used as a tool to mark out distances, in particular, on maps. Compasses can be used for mathematics, drafting ...
Each generator halves the number of runs required. A design with p such generators is a 1/(l p)=l −p fraction of the full factorial design. [3] For example, a 2 5 − 2 design is 1/4 of a two-level, five-factor factorial design. Rather than the 32 runs that would be required for the full 2 5 factorial experiment, this experiment requires only ...
The Philips PM5540 was an early electronic video signal generator, which generated a monochrome test card [3] that is considered to be a black-and-white predecessor of the widely used Philips PM5544 and the latter's related family of Philips circle test patterns. The content and layout of the pattern, as well as the generator, was designed and ...
Set v n+1 = 1 / 2 (v n + p r n), where r n is a random number 1, 2 or 3. Draw the points v 1 to v ∞. If the first point v 1 was a point on the Sierpiński triangle, then all the points v n lie on the Sierpiński triangle.
An illustration of Monte Carlo integration. In this example, the domain D is the inner circle and the domain E is the square. Because the square's area (4) can be easily calculated, the area of the circle (π*1.0 2) can be estimated by the ratio (0.8) of the points inside the circle (40) to the total number of points (50), yielding an approximation for the circle's area of 4*0.8 = 3.2 ≈ π.
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