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  2. Harbour (programming language) - Wikipedia

    en.wikipedia.org/wiki/Harbour_(programming_language)

    The LiteralExp must be a compiled time resolvable numeric expression, and may involve operators, as long as such operators involve compile time static value. The EXIT optional statement is the equivalent of the C statement break , and if present, execution of the SWITCH structure will end when the EXIT statement is reached, otherwise it will ...

  3. Most vexing parse - Wikipedia

    en.wikipedia.org/wiki/Most_vexing_parse

    The most vexing parse is a counterintuitive form of syntactic ambiguity resolution in the C++ programming language. In certain situations, the C++ grammar cannot distinguish between the creation of an object parameter and specification of a function's type. In those situations, the compiler is required to interpret the line as a function type ...

  4. Augmented assignment - Wikipedia

    en.wikipedia.org/wiki/Augmented_assignment

    Augmented assignment (or compound assignment) is the name given to certain assignment operators in certain programming languages (especially those derived from C).An augmented assignment is generally used to replace a statement where an operator takes a variable as one of its arguments and then assigns the result back to the same variable.

  5. Operators in C and C++ - Wikipedia

    en.wikipedia.org/wiki/Operators_in_C_and_C++

    All the operators (except typeof) listed exist in C++; the column "Included in C", states whether an operator is also present in C. Note that C does not support operator overloading. When not overloaded, for the operators && , || , and , (the comma operator ), there is a sequence point after the evaluation of the first operand.

  6. C++ - Wikipedia

    en.wikipedia.org/wiki/C++

    The rich set of overloadable operators is central to making user-defined types in C++ seem like built-in types. Overloadable operators are also an essential part of many advanced C++ programming techniques, such as smart pointers. Overloading an operator does not change the precedence of calculations involving the operator, nor does it change ...

  7. Compatibility of C and C++ - Wikipedia

    en.wikipedia.org/wiki/Compatibility_of_C_and_C++

    C++ enforces stricter typing rules (no implicit violations of the static type system [1]), and initialization requirements (compile-time enforcement that in-scope variables do not have initialization subverted) [7] than C, and so some valid C code is invalid in C++. A rationale for these is provided in Annex C.1 of the ISO C++ standard.

  8. Ellipsis (computer programming) - Wikipedia

    en.wikipedia.org/.../Ellipsis_(computer_programming)

    operator in scalar context as a flip-flop operator - a stateful bistable Boolean test, roughly equivalent to "true while x but not yet y", similarly to the "," operator in sed and AWK. [1] GNU C compatible compilers have an extension to the C and C++ language to allow case ranges in switch statements:

  9. Common operator notation - Wikipedia

    en.wikipedia.org/wiki/Common_operator_notation

    If so, a statement like a := b := c would be equivalent to a := (b := c), which means that the value of c is copied to b which is then copied to a. An operator which is non-associative cannot compete for operands with operators of equal precedence. In Prolog for example, the infix operator :-is non-associative, so constructs such as a :- b :- c ...