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  2. Balls into bins problem - Wikipedia

    en.wikipedia.org/wiki/Balls_into_bins_problem

    (All the bounds hold with probability at least / for any constant >.) Note that for m > n log ⁡ n {\displaystyle m>n\log n} , the random allocation process gives only the maximum load of m n + O ( log ⁡ log ⁡ n ) {\displaystyle {\frac {m}{n}}+O\left(\log \log n\right)} with high probability, so the improvement between these two processes ...

  3. Stars and bars (combinatorics) - Wikipedia

    en.wikipedia.org/wiki/Stars_and_bars_(combinatorics)

    The solution to this particular problem is given by the binomial coefficient (+), which is the number of subsets of size k − 1 that can be formed from a set of size n + k − 1. If, for example, there are two balls and three bins, then the number of ways of placing the balls is ( 2 + 3 − 1 3 − 1 ) = ( 4 2 ) = 6 {\displaystyle {\tbinom {2 ...

  4. Newton–Pepys problem - Wikipedia

    en.wikipedia.org/wiki/Newton–Pepys_problem

    The Newton–Pepys problem is a probability problem concerning the probability of throwing sixes from a certain number of dice. [1] In 1693 Samuel Pepys and Isaac Newton corresponded over a problem posed to Pepys by a school teacher named John Smith. [2] The problem was: Which of the following three propositions has the greatest chance of success?

  5. 100 prisoners problem - Wikipedia

    en.wikipedia.org/wiki/100_prisoners_problem

    Probability distribution of the length of the longest cycle of a random permutation of the numbers 1 to 100. The green area corresponds to the survival probability of the prisoners. In the initial problem, the 100 prisoners are successful if the longest cycle of the permutation has a length of at most 50.

  6. Bertrand's ballot theorem - Wikipedia

    en.wikipedia.org/wiki/Bertrand's_ballot_theorem

    Then considering the case with p = a and q = b, the last vote counted is either for the first candidate with probability a/(a + b), or for the second with probability b/(a + b). So the probability of the first being ahead throughout the count to the penultimate vote counted (and also after the final vote) is:

  7. Urn problem - Wikipedia

    en.wikipedia.org/wiki/Urn_problem

    In probability and statistics, an urn problem is an idealized mental exercise in which some objects of real interest (such as atoms, people, cars, etc.) are represented as colored balls in an urn or other container. One pretends to remove one or more balls from the urn; the goal is to determine the probability of drawing one color or another ...

  8. Moral Injury - The Huffington Post

    projects.huffingtonpost.com/moral-injury/joseph...

    He would blow off his homework and then ace his tests. By the 5th grade, at the red-brick Hamilton Avenue School in nearby Greenwich, he’d published three poems in the school newspaper. One, written after a class lecture about drinking and driving, described the thoughts of a driver as he was dying in a car crash. At school, Joseph was bullied.

  9. Product-form solution - Wikipedia

    en.wikipedia.org/wiki/Product-form_solution

    In probability theory, a product-form solution is a particularly efficient form of solution for determining some metric of a system with distinct sub-components, where the metric for the collection of components can be written as a product of the metric across the different components.