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  2. Square pyramid - Wikipedia

    en.wikipedia.org/wiki/Square_pyramid

    If the apex of the pyramid is directly above the center of the square, it is a right square pyramid with four isosceles triangles; otherwise, it is an oblique square pyramid. When all of the pyramid's edges are equal in length, its triangles are all equilateral. It is called an equilateral square pyramid, an example of a Johnson solid.

  3. Frustum - Wikipedia

    en.wikipedia.org/wiki/Frustum

    The formula for the volume of a pyramidal square frustum was introduced by the ancient Egyptian mathematics in what is called the Moscow Mathematical Papyrus, written in the 13th dynasty (c. 1850 BC): = (+ +), where a and b are the base and top side lengths, and h is the height.

  4. Pyramid (geometry) - Wikipedia

    en.wikipedia.org/wiki/Pyramid_(geometry)

    Given that is the base's area and is the height of a pyramid, the volume of a pyramid is: [25] =. The volume of a pyramid was recorded back in ancient Egypt, where they calculated the volume of a square frustum, suggesting they acquainted the volume of a square pyramid. [26]

  5. Rhind Mathematical Papyrus - Wikipedia

    en.wikipedia.org/wiki/Rhind_Mathematical_Papyrus

    to calculate the volume of a cylindrical grain silo with a diameter of 9 cubits and a height of 10 cubits. Give the answer in terms of cubic cubits. Furthermore, given the following equalities among other units of volume, 1 cubic cubit = 3/2 khar = 30 heqats = 15/2 quadruple heqats, also express the answer in terms of khar and quadruple heqats.

  6. Egyptian geometry - Wikipedia

    en.wikipedia.org/wiki/Egyptian_geometry

    Obtaining a better approximation to the area using finer divisions of a square and a similar argument is not simple. [10] Problem 50 of the RMP finds the area of a round field of diameter 9 khet. [10] This is solved by using the approximation that circular field of diameter 9 has the same area as a square of side 8.

  7. Moscow Mathematical Papyrus - Wikipedia

    en.wikipedia.org/wiki/Moscow_Mathematical_Papyrus

    The fourteenth problem of the Moscow Mathematical calculates the volume of a frustum. Problem 14 states that a pyramid has been truncated in such a way that the top area is a square of length 2 units, the bottom a square of length 4 units, and the height 6 units, as shown. The volume is found to be 56 cubic units, which is correct. [1]

  8. Hornets apologize after pretending to give child PS5 and ...

    www.aol.com/sports/hornets-apologize-pretending...

    A day after receiving criticism for a skit in which a child was "given" a PlayStation 5 then had it taken away, the Hornets apologized and announced in a statement they were making things right.

  9. Bipyramid - Wikipedia

    en.wikipedia.org/wiki/Bipyramid

    In geometry, a bipyramid, dipyramid, or double pyramid is a polyhedron formed by fusing two pyramids together base-to-base.The polygonal base of each pyramid must therefore be the same, and unless otherwise specified the base vertices are usually coplanar and a bipyramid is usually symmetric, meaning the two pyramids are mirror images across their common base plane.