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f[x_] := x^1.1 - 2.5 x^.5. And also knowing that the formula of the tangent line is. f'[x](x-a) + f[a] You could just make a Plot with it. With a=1, as you requested: Here is the code of it: With[. {a = 1}, Plot[.
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Certainly, there is a better way: y[x_] := 2 x Sin[x]; a = Pi/2; Collect[Normal[Series[y[x], {x, a, 1}]], x, Simplify]
The tangent line goes through the point P (0, 0), calculate the slope and plot it:
0. Find the equation of the tangent line for the following function. Then plot the original equation and the tangent line on the same graph. 𝑥 =cos (𝜋𝑡) 𝑦=𝑡3 +2𝑡 (0,9/8) This looks like a homework question.
Find an equation to the tangent of the curve at the given point. Then graph the curve and the tangent. $$x=t^2-t,\\quad y=t^2+t+1; \\quad(0,3)$$ I can do this with a ...
Therefore, the slope of the line tangent to x^2+x y+y^2==3 at the point pt={1,1} is equal to. pt = {1, 1}; eq = x^2 + x y + y^2; slope = -D[eq, x]/D[eq, y] /. Thread[{x, y} -> pt]; And the tangent line is equal to. line[x_] := pt[[2]] + (x - pt[[1]]) slope To show that the line is indeed tangent at {1,1}:
At the point Fun1, draw a tangent line at that point to the curve. At another point where the curve and the tangent intersect I need to mark it with “Fun2”.The area between the segment Fun1Fun2 and the curve should be denoted "A” Now I need to find at point Fun2, the tangent line, and this tangent intersects the curve again at "Fun3".
This post was edited and submitted for review 2 years ago and failed to reopen the post: Original close reason (s) were not resolved. I have to plot a function and the tangent line and I don't know how to do it. It has to be one plot. function: f [x_]= Sin [x] and the tangent line for the function is x=0. Other questions didn't help me so I ...
I need to find the equation of the tangent lines at the points where the tangent line has a slope of 4. Then I must verify my results by plotting the graph of y = f(x) along with the tangent lines in a range which includes the x-coordinates I have found.