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12 because you have to do the multiplication before you can add. 1+1+1+1+1+1+1+1+1+1+1+1x0+1=. So you replace the 1x0 by 0 and you have. 1+1+1+1+1+1+1+1+1+1+1+0+1=. Now there are no multiplications left so you can add and get 12. Edwin.
You can put this solution on YOUR website! a^n -1=(a-1)(a^(n-1) + a^(n-2) +.....+ a+1) We need to prove that it is true for n=1 or n=2,and
Question 176007: Hi guys and gals! How can 1 1 1 = 6 ? I am completely stumped on the first part of a riddle I'm sure some of you know about. Commonly called "The 6 Riddle", it states that all you do is insert the appropriate mat
1 1 1 -1 11 -40 101 153 2 2 0 10 -29 61 254 4 2 10 -19 32 315 6 12 -9 13 347 18 3 4 360 ...
Question 346582: Hello I seem to be stuck at this problem. I'm not to sure how to write it as the n and n-1 are subscripts.
You can put this solution on YOUR website! 1,8,27,64,__, __, __,__, __,1000 8 = 2 * 2 * 2 27 = 3 * 3* 3 64 = 4 * 4 *4
1-1-1+1+1-1+2= 2 Case2 if say c=1, a=b=-1, then ab+bc+ac+a+b+c+2= 1-1-1-1-1+1+2= 0 Minimum value is 0 ...
Question 82554: Find the next term of the sequence. 1, 8, 27, 64, ... What is the formula for the following arithmetic sequence?
You can put this solution on YOUR website! Take note that we can combine the terms of to get Now take note that the second numerator (2) cancels out with the first denominator (2).
Question 1136758: Given p(x)=x^3+x^2+x+1. Write P(x) in factored form. Be sure to write the full equation including P(x)?