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The people of Ancient Egypt stood around 167 cm (5 ft 6 in) for males and 157 cm (5 ft 2 in) for females. [64] The Ancient Greeks averaged 166 cm (5 ft 5 in) for males and 154 cm (5 ft 1 in) for females. The Romans were slightly taller, with an average height of 169 cm (5 ft 7 in) for males and 158 cm (5 ft 2 in) for females. [65]
Answer: 5 + 8 + 3 + 2 + 6 = 24. This is arrived at by simple summation of the sequence. But if we regarded 18 as the running total, we need only add 6 to 18 to get 24. So, 18 was, and 24 now is, the running total. In fact, we would not even need to know the sequence at all, but simply add 6 to 18 to get the new running total; as each new number ...
Grading scales can be 1 to 8, 1 to 4, or A through G, where A is on a 4.0 scale or on a 5.0 scale. The most common scale is now 1 to 7, with 9 being the highest grade obtained. In addition, degrees are awarded in a Class, depending on the grades received.
(1) of Percaru and Berckhemer (1978) for the magnitude range 5.0 ≤ M s ≤ 7.5 is not reliable due to the inconsistency of defined magnitude range (moderate to large earthquakes defined as M s ≤ 7.0 and M s = 7–7.5) and scarce data in lower magnitude range (≤ 7.0) which rarely represents the global seismicity (e.g., see Figs. 1A, B, 4 ...
For a $400,000 loan, choosing a 5/1 ARM at 6.30% instead of a 7% fixed rate could save you $514 monthly during the initial period — $2,476 versus $2,990. However, when the initial period ends in ...
In a typical 6/49 game, each player chooses six distinct numbers from a range of 1–49. If the six numbers on a ticket match the numbers drawn by the lottery, the ticket holder is a jackpot winner—regardless of the order of the numbers.
Operating expenses were $112.0 million, an increase of 60.4% compared to $70.0 million in the fourth quarter of last year. ... Total outstanding debt was $696.2 million ($709.3 million of debt ...
Continuing similarly to search for a 3-combination at position 16 − 15 = 1 one finds c 3 = 3, which uses up the final unit; this establishes = + + (), and the remaining values c i will be the maximal ones with () =, namely c i = i − 1. Thus we have found the 5-combination {8, 6, 3, 1, 0}.