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For gases, departure from 3 R per mole of atoms is generally due to two factors: (1) failure of the higher quantum-energy-spaced vibration modes in gas molecules to be excited at room temperature, and (2) loss of potential energy degree of freedom for small gas molecules, simply because most of their atoms are not bonded maximally in space to ...
Carbon monoxide: 1.505 0.0398500 Carbon tetrachloride: ... 1 L 2 atm/mol 2 = 0.101325 J·m 3 /mol 2 = 0.101325 Pa·m 6 ... (where kmol is kilomoles = 1000 moles ...
The molar mass of atoms of an element is given by the relative atomic mass of the element multiplied by the molar mass constant, M u ≈ 1.000 000 × 10 −3 kg/mol ≈ 1 g/mol. For normal samples from Earth with typical isotope composition, the atomic weight can be approximated by the standard atomic weight [2] or the conventional atomic weight.
The mole is widely used in chemistry as a convenient way to express amounts of reactants and amounts of products of chemical reactions. For example, the chemical equation 2 H 2 + O 2 → 2 H 2 O can be interpreted to mean that for each 2 mol molecular hydrogen (H 2) and 1 mol molecular oxygen (O 2) that react, 2 mol of water (H 2 O) form.
1.9 Carbon: Gas C 716.67 Carbon dioxide: Gas CO 2: −393.509 Carbon disulfide: Liquid CS 2: 89.41 Carbon disulfide: Gas CS 2: 116.7 Carbon monoxide: Gas CO −110.525 Carbonyl chloride Gas COCl 2: −218.8 Carbon dioxide (un–ionized) Aqueous CO 2 (aq) −419.26 Bicarbonate ion Aqueous HCO 3 – −689.93 Carbonate ion Aqueous CO 3 2– − ...
For example, sulfuric acid (H 2 SO 4) is a diprotic acid. Since only 0.5 mol of H 2 SO 4 are needed to neutralize 1 mol of OH −, the equivalence factor is: f eq (H 2 SO 4) = 0.5. If the concentration of a sulfuric acid solution is c(H 2 SO 4) = 1 mol/L, then its normality is 2 N. It can also be called a "2 normal" solution.
From this table we see that the number of hydrogen and chlorine atoms on the product's side are twice the number of atoms on the reactant's side. Therefore, we add the coefficient "2" in front of the HCl on the products side, to get the equation to look like this:
c V,m = 1 / 2 fR. where R is the ideal gas constant. According to Mayer's relation, the molar heat capacity at constant pressure would be c P,m = c V,m + R = 1 / 2 fR + R = 1 / 2 (f + 2)R. Thus, each additional degree of freedom will contribute 1 / 2 R to the molar heat capacity of the gas (both c V,m and c P,m).