Search results
Results from the WOW.Com Content Network
51. In python, as far as I know, there are at least 3 to 4 ways to create and initialize lists of a given size: Simple loop with append: my_list.append(0) Simple loop with +=: my_list += [0] List comprehension: List and integer multiplication:
A list of lists named xss can be flattened using a nested list comprehension: flat_list = [ x for xs in xss for x in xs ] The above is equivalent to: flat_list = [] for xs in xss: for x in xs: flat_list.append(x) Here is the corresponding function: def flatten(xss): return [x for xs in xss for x in xs]
set - unordered collection of unique elements. List of elements can be passed to set's constructor. So, pass list with duplicate elements, we get set with unique elements and transform it back to list then get list with unique elements. I can say nothing about performance and memory overhead, but I hope, it's not so important with small lists.
This solution will create a separate list containing the lowercase items, regardless of their original case. If the original case is upper then the list s will contain lowercase of the respective item in list p. If the original case of the list item is already lowercase in list p then the list s will
@loved.by.Jesus: Yeah, they added optimizations for Python level method calls in 3.7 that were extended to C extension method calls in 3.8 by PEP 590 that remove the overhead of creating a bound method each time you call a method, so the cost to call alist.copy() is now a dict lookup on the list type, then a relatively cheap no-arg function call that ultimately invokes the same thing as slicing.
In python an easy way is: your_list = [] for i in range(10): your_list.append(i) You can also get your for in a single line like so: your_list = [] for i in range(10): your_list.append(i) Don't ever get discouraged by other people's opinions, specially for new learners.
float(item) do the right thing: it converts its argument to float and and return it, but it doesn't change argument in-place. A simple fix for your code is: new_list = [] for item in list: new_list.append(float(item)) The same code can written shorter using list comprehension: new_list = [float(i) for i in list]
Agree with @Bogdan. This answer creates a string in which the list elements are joined together with no whitespace or comma in between. You can use ', '.join(list1) to join the elements of the list with comma and whitespace or ' '.join(to) to join with only white space –
That is a list in Python 2.x and behaves mostly like a list in Python 3.x. If you are running Python 3 and ...
joined_list = [item for list_ in [list_one, list_two] for item in list_] It has all the advantages of the newest approach of using Additional Unpacking Generalizations - i.e. you can concatenate an arbitrary number of different iterables (for example, lists, tuples, ranges, and generators) that way - and it's not limited to Python 3.5 or later.