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Torque; system unit code symbol or abbrev. notes conversion factor/N⋅m combinations Industrial: SI: Newton-metre: Nm N⋅m 1 Nm lbft; Nm lbfft; Non-SI metric: kilogram-metre: kgm kg·m 9.80665 Imperial & US customary: pound-foot: lbft lb⋅ft Pound-inch (lb.in) is also available 1.3558 Scientific: SI: newton metre: Nm N⋅m 1 Nm lbft; Nm ...
kilogram per cubic metre (SI unit) kg/m 3: ≡ kg/m 3 = 1 kg/m 3: kilogram per litre kg/L ≡ kg/L = 1000 kg/m 3: ounce (avoirdupois) per cubic foot oz/ft 3: ≡ oz/ft 3: ≈ 1.001 153 961 kg/m 3: ounce (avoirdupois) per cubic inch oz/in 3: ≡ oz/in 3: ≈ 1.729 994 044 × 10 3 kg/m 3: ounce (avoirdupois) per gallon (imperial) oz/gal ≡ oz ...
is the motor torque constant (SI unit, newton–metre per ampere, N·m/A), see below If two motors with the same K v {\displaystyle K_{\text{v}}} and torque work in tandem, with rigidly connected shafts, the K v {\displaystyle K_{\text{v}}} of the system is still the same assuming a parallel electrical connection.
The value in Système International (SI) units is given by multiplying the following exact factors: One pound (mass) = 0.453 592 37 kilograms [1] Standard gravity = 9.80665 m/s 2 [1] One foot = 0.3048 m [1] This gives the exact conversion factor: One pound-foot = 1.355 817 948 331 400 4 newton metres.
If Imperial units are used, and if torque is in pounds-force feet and rotational speed in revolutions per minute, the above equation gives power in foot pounds-force per minute. The horsepower form of the equation is then derived by applying the conversion factor 33,000 ft⋅lbf/min per horsepower:
For example, 10 miles per hour can be converted to metres per second by using a sequence of conversion factors as shown below: = . Each conversion factor is chosen based on the relationship between one of the original units and one of the desired units (or some intermediary unit), before being rearranged to create a factor that cancels out the ...
Both energy and torque can be expressed as a product of a force vector with a displacement vector (hence pounds and feet); energy is the scalar product of the two, and torque is the vector product. Although calling the torque unit "pound-foot" has been academically suggested, both are still commonly called "foot-pound" in colloquial usage.
A typical turbocharged V8 diesel engine might have an engine power of 250 kW (340 hp) and a mass of 380 kg (840 lb), [1] giving it a power-to-weight ratio of 0.65 kW/kg (0.40 hp/lb). Examples of high power-to-weight ratios can often be found in turbines. This is because of their ability to operate at very high speeds.