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  2. Proof of impossibility - Wikipedia

    en.wikipedia.org/wiki/Proof_of_impossibility

    A more general proof shows that the mth root of an integer N is irrational, unless N is the mth power of an integer n. [7] That is, it is impossible to express the mth root of an integer N as the ratio a ⁄ b of two integers a and b, that share no common prime factor, except in cases in which b = 1.

  3. Irrational number - Wikipedia

    en.wikipedia.org/wiki/Irrational_number

    Here is a proof by contradiction that log 2 3 is irrational (log 2 3 ≈ 1.58 > 0). Assume log 2 3 is rational. For some positive integers m and n , we have

  4. Transcendental number - Wikipedia

    en.wikipedia.org/wiki/Transcendental_number

    For example, the square root of 2 is an irrational number, but it is not a transcendental number as it is a root of the polynomial equation x 2 − 2 = 0. The golden ratio (denoted or ) is another irrational number that is not transcendental, as it is a root of the polynomial equation x 2 − x − 1 = 0.

  5. Square root of 7 - Wikipedia

    en.wikipedia.org/wiki/Square_root_of_7

    A Logarex system Darmstadt slide rule with 7 and 6 on A and B scales, and square roots of 6 and of 7 on C and D scales, which can be read as slightly less than 2.45 and somewhat more than 2.64, respectively. The square root of 7 is the positive real number that, when multiplied by itself, gives the prime number 7.

  6. Algebraic number - Wikipedia

    en.wikipedia.org/wiki/Algebraic_number

    Likewise, tan ⁠ 3 π / 16 ⁠, tan ⁠ 7 π / 16 ⁠, tan ⁠ 11 π / 16 ⁠, and tan ⁠ 15 π / 16 ⁠ satisfy the irreducible polynomial x 4 − 4x 3 − 6x 2 + 4x + 1 = 0, and so are conjugate algebraic integers. This is the equivalent of angles which, when measured in degrees, have rational numbers. [2] Some but not all irrational ...

  7. Complex conjugate root theorem - Wikipedia

    en.wikipedia.org/wiki/Complex_conjugate_root_theorem

    This requires some care in the presence of multiple roots; but a complex root and its conjugate do have the same multiplicity (and this lemma is not hard to prove). It can also be worked around by considering only irreducible polynomials ; any real polynomial of odd degree must have an irreducible factor of odd degree, which (having no multiple ...

  8. nth root - Wikipedia

    en.wikipedia.org/wiki/Nth_root

    A root of degree 2 is called a square root and a root of degree 3, a cube root. Roots of higher degree are referred by using ordinal numbers, as in fourth root, twentieth root, etc. The computation of an n th root is a root extraction. For example, 3 is a square root of 9, since 3 2 = 9, and −3 is also a square root of 9, since (−3) 2 = 9.

  9. Cyclotomic polynomial - Wikipedia

    en.wikipedia.org/wiki/Cyclotomic_polynomial

    k is a non-negative integer, always equal to 0 when b is even. (In fact, if n is neither 1 nor 2, then k is either 0 or 1. Besides, if n is not a power of 2, then k is always equal to 0) g is 1 or the largest odd prime factor of n. h is odd, coprime with n, and its prime factors are exactly the odd primes p such that n is the multiplicative ...