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I'm trying to work a physics problem about how to find the coefficient of static friction between two objects when given the initial velocity and distance. Specifically, the problem I am working is as follows: A crate is carried in a pickup truck traveling horizontally at 14.2 m/s.
Friction is (at a first approximation) a pressure tangential to the surface of contact between two bodies, directed against the movement, and proportional to the contact pressure, by the coefficient of friction μ μ. Thus totally it is equal to μmg μ m g, and will exert a deceleration equal to μg μ g. The law of accelerated motion gives v1 ...
On the surface of the spring there is friction whose coefficient is u. The spring is pulled a distance A from its equilibrium point. I derived a differential equation for this following system: F = ma. −kx + umg = md2x dt2. d2x dt2 + k mx = ug, x(0) = A,x′(0) = 0. Since there is friction in the system, I would expect the spring to come to a ...
It follows that ˙p = M¨y. Let m be the mass of the vertical section, corresponding to y. Then the force on the chain is mg. Let λ = M / ℓ be the linear mass density. Newton's Second Law then tells us that mg = M¨y λyg = M¨y M ℓ yg = M¨y ¨y = g ℓ y. This DE has the solution y = Aet√g / ℓ + Be − t√g / ℓ.
A speedway has banked turns of 31° and a radius of 304.8 m. Drivers can go through the corners at a speed of 322 km/h before slipping. What is the coefficient of friction between the tires and the road? Is there a generic formula that I could use? If not could I get some help working this out? Thanks in advance.
1. Let the x x axis be along the road, downwards and let the y y axis be perpendicular to the road upwards. Projection of gravitational acceleration on the x-axis is g sinθ g sin θ and −g cosθ − g cos θ on the y-axis. Friction is along the negative x x axis and is Fxf = −γvx F x f = − γ v x. Newton along x x is.
The coefficient of friction between rope and post is $0.25$. It is desired that by pulling with a force of $1N$ on one end of the rope, I can prevent the rope from moving away from me even if a force of $10^6N$ is applied to the other end.
You are running on an icy sidewalk. Suddenly, you stop running and let yourself slide. You slide at an initial speed of 10 m/s. You slide for a distance of 16 meters and your final speed, when you stop sliding, is 7 m/s. With a mass of 60 kilograms, what is the force of kinetic friction of the ice? Any help is appreciated. Thanks
A skier, moving at 8m/s, slides to a stop on a level surface while moving 64m. Assuming her mass to be 60kg, what is the coefficient of friction between her skies and the snow?
Q.) A car rounds a turn of radius 120 m on a flat road. If the coefficient of friction between the tires and the road is 0.50, what is the maximum speed of the car without skidding? I really don't get this problem. I get that centripetal force= mass* (velocity^2/radius) and frictional force = coefficient of friction*Normal force.