Search results
Results from the WOW.Com Content Network
It can only be used to draw a line segment between two points, or to extend an existing line segment. The compass can have an arbitrarily large radius with no markings on it (unlike certain real-world compasses). Circles and circular arcs can be drawn starting from two given points: the centre and a point on the circle. The compass may or may ...
The pedal triangles of the first and second Brocard points are congruent to each other and similar to the original triangle. [4] If the lines AP, BP, CP, each through one of a triangle's vertices and its first Brocard point, intersect the triangle's circumcircle at points L, M, N, then the triangle LMN is congruent with the original triangle ABC.
In elementary geometry the word congruent is often used as follows. [2] The word equal is often used in place of congruent for these objects. Two line segments are congruent if they have the same length. Two angles are congruent if they have the same measure. Two circles are congruent if they have the same diameter.
To draw the parallel (h) to a diameter g through any given point P. Chose auxiliary point C anywhere on the straight line through B and P outside of BP. (Steiner) In the branch of mathematics known as Euclidean geometry, the Poncelet–Steiner theorem is one of several results concerning compass and straightedge constructions having additional restrictions imposed on the traditional rules.
Two Saccheri quadrilaterals are congruent if: the base segments and summit angles are congruent; the summit segments and summit angles are congruent. The line segment joining the midpoint of the base and the midpoint of the summit: Is perpendicular to the base and the summit, is the only line of symmetry of the quadrilateral,
When two cells in the Voronoi diagram share a boundary, it is a line segment, ray, or line, consisting of all the points in the plane that are equidistant to their two nearest sites. The vertices of the diagram, where three or more of these boundaries meet, are the points that have three or more equally distant nearest sites.
To construct the inverse P ' of a point P outside a circle Ø: Draw the segment from O (center of circle Ø) to P. Let M be the midpoint of OP. (Not shown) Draw the circle c with center M going through P. (Not labeled. It's the blue circle) Let N and N ' be the points where Ø and c intersect. Draw segment NN '. P ' is where OP and NN ' intersect.
Construct the line segment BB' and using a hyperbolic ruler, construct the line OI" such that OI" is perpendicular to BB' and parallel to B'I". Then, line OA is the angle bisector for ᗉ IAI'. [3] Case 2c: IB' is ultraparallel to I'B. Using the ultraparallel theorem, construct the common perpendicular of IB' and I'B, CC'. Let the intersection ...