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This variation of the birthday problem is interesting because there is not a unique solution for the total number of people m + n. For example, the usual 50% probability value is realized for both a 32-member group of 16 men and 16 women and a 49-member group of 43 women and 6 men.
The problem in Equihash is to find distinct, -bit values ,,..., to satisfy () ()... = such that (...) has leading zeros, where is a chosen hash function. [1] In addition, there are "algorithm binding conditions" which are intended to reduce the risk of other algorithms developed to solve the underlying birthday problem being applicable.
A naive application of the even-odd rule gives (,) = = () ()where P(m,n) is the probability of m people having all of n possible birthdays. At least for P(4,7) this formula gives the same answer as above, 525/1024 = 8400/16384, so I'm fairly confident it's right.
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The birthday attack can be modeled as a variation of the balls and bins problem. In this problem: Balls represent inputs to the hash function. Bins represent possible outputs of the hash function (hash values). A collision occurs when two or more balls land in the same bin (i.e., two inputs produce the same hash output).
The problem to determine all positive integers such that the concatenation of and in base uses at most distinct characters for and fixed [citation needed] and many other problems in the coding theory are also the unsolved problems in mathematics.
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Cheryl's Birthday" is a logic puzzle, specifically a knowledge puzzle. [ 1 ] [ 2 ] The objective is to determine the birthday of a girl named Cheryl using a handful of clues given to her friends Albert and Bernard.