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2. Wheel sizing - Wikipedia

   en.wikipedia.org/wiki/Wheel_sizing

   Off-roading tires may use a different measurement scheme: Tread width × Outside diameter, followed by wheel size (all in inches) – for example 31×10.50R15 (787 mm × 267 mm R380 in metric designation). The size of the wheel, however, is denoted as 8.5 in × 20.0 in (220 mm × 510 mm).

3. Tire code - Wikipedia

   en.wikipedia.org/wiki/Tire_code

   As an example, if a tire size has two sets of numbers (6-12, 5.00-15, 11.2-24), then the first number (5.00-15) is the approximate width in inches, and the second number (5.00-15) is the rim diameter in inches. If a tire size has three sets of numbers (15x6.00-6, 26x12.00-12, 31x15.50-15), then the first number (26x12.00-12) is the approximate ...

4. Goodyear Polyglas tire - Wikipedia

   en.wikipedia.org/wiki/Goodyear_Polyglas_tire

   The polyester sidewalls provided stability for heavy cars at low inflation pressures. The features increased the mileage and enhanced road-holding performance. The objective was to gain the radial tire's longer tread life and a firmer road grip in a bias-belted tire. [3] The Polyglas tires featured a wide footprint. [4]

5. Formula One tyres - Wikipedia

   en.wikipedia.org/wiki/Formula_One_tyres

   [4] 1975's Ferrari 312T used a Goodyear 26.0"×16.2"–13" slick tyre (overall diameter × width) in the rear on a 13"×18" rim, with a Goodyear 20.0"×9.2"–13" slick tyre in the front on a 13×10" rim. [5] For the 1981 season the maximum diameter of the rear tyre was limited to 26.0", while the diameter of the front tyres was increased.

6. Tire maintenance - Wikipedia

   en.wikipedia.org/wiki/Tire_maintenance

   The chief reason for tire replacement is friction from moving contact with road surfaces, causing the tread on the outer perimeter of tires to eventually wear away. When the tread depth becomes too shallow, like for example below 3.2 mm (4/32 in), the tire is worn out and should be replaced.

7. Bicycle tire - Wikipedia

   en.wikipedia.org/wiki/Bicycle_tire

   For example, if a fat-bike tire is inflated to 0.5 bar (50 kPa; 7.3 psi) gauge pressure at room temperature 20 °C (68 °F) and then the temperature is decreased to −10 °C (14 °F) (a 9% decrease in absolute temperature), the absolute pressure of 1.5 bar (150 kPa; 22 psi) will be decreased by 9% to 1.35 bar (135 kPa; 19.6 psi), which ...