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  2. Euclidean algorithm - Wikipedia

    en.wikipedia.org/wiki/Euclidean_algorithm

    For example, 6 and 35 factor as 6 = 2 × 3 and 35 = 5 × 7, so they are not prime, but their prime factors are different, so 6 and 35 are coprime, with no common factors other than 1. A 24×60 rectangle is covered with ten 12×12 square tiles, where 12 is the GCD of 24 and 60.

  3. Greatest common divisor - Wikipedia

    en.wikipedia.org/wiki/Greatest_common_divisor

    If one uses the Euclidean algorithm and the elementary algorithms for multiplication and division, the computation of the greatest common divisor of two integers of at most n bits is O(n 2). This means that the computation of greatest common divisor has, up to a constant factor, the same complexity as the multiplication.

  4. Polynomial greatest common divisor - Wikipedia

    en.wikipedia.org/wiki/Polynomial_greatest_common...

    Then, take the product of all common factors. At this stage, we do not necessarily have a monic polynomial, so finally multiply this by a constant to make it a monic polynomial. This will be the GCD of the two polynomials as it includes all common divisors and is monic. Example one: Find the GCD of x 2 + 7x + 6 and x 2 − 5x − 6.

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  7. Musk now says it's 'pointless' to build a $25,000 Tesla for ...

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    The April 5 Reuters article reported that Tesla had abandoned plans for an all-new, affordable mass-market EV but still planned a self-driving robotaxi. Since then, Musk has increasingly touted ...

  8. GDP: US economy grows at slower-than-expected pace in third ...

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    The Bureau of Economic Analysis's advance estimate of third quarter US gross domestic product (GDP) showed the economy grew at an annualized pace of 2.8% during the period, below the 2.9% growth ...

  9. Factorization of polynomials - Wikipedia

    en.wikipedia.org/wiki/Factorization_of_polynomials

    These factors modulo need not correspond to "true" factors of () in [], but we can easily test them by division in []. This way, all irreducible true factors can be found by checking at most 2 r {\displaystyle 2^{r}} cases, reduced to 2 r − 1 {\displaystyle 2^{r-1}} cases by skipping complements.

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