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  2. Equation solving - Wikipedia

    en.wikipedia.org/wiki/Equation_solving

    For example, the equation x + y = 2x – 1 is solved for the unknown x by the expression x = y + 1, because substituting y + 1 for x in the equation results in (y + 1) + y = 2(y + 1) – 1, a true statement. It is also possible to take the variable y to be the unknown, and then the equation is solved by y = x – 1.

  3. Elementary algebra - Wikipedia

    en.wikipedia.org/wiki/Elementary_algebra

    To solve this kind of equation, the technique is add, subtract, multiply, or divide both sides of the equation by the same number in order to isolate the variable on one side of the equation. Once the variable is isolated, the other side of the equation is the value of the variable. [ 37 ]

  4. Indeterminate equation - Wikipedia

    en.wikipedia.org/wiki/Indeterminate_equation

    In mathematics, particularly in algebra, an indeterminate equation is an equation for which there is more than one solution. [1] For example, the equation + = is a simple indeterminate equation, as is =. Indeterminate equations cannot be solved uniquely. In fact, in some cases it might even have infinitely many solutions. [2] Some of the ...

  5. Equation - Wikipedia

    en.wikipedia.org/wiki/Equation

    [2] [3] The word equation and its cognates in other languages may have subtly different meanings; for example, in French an équation is defined as containing one or more variables, while in English, any well-formed formula consisting of two expressions related with an equals sign is an equation. [4] Solving an equation containing variables ...

  6. Cubic equation - Wikipedia

    en.wikipedia.org/wiki/Cubic_equation

    In algebra, a cubic equation in one variable is an equation of ... if the polynomial is square-free. If r 1, r 2, ... For solving the cubic equation x 3 + m 2 x = n ...

  7. Equating coefficients - Wikipedia

    en.wikipedia.org/wiki/Equating_coefficients

    The unique pair of values a, b satisfying the first two equations is (a, b) = (1, 1); since these values also satisfy the third equation, there do in fact exist a, b such that a times the original first equation plus b times the original second equation equals the original third equation; we conclude that the third equation is linearly ...

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