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In a subnormal number, since the exponent is the least that it can be, zero is the leading significant digit (0.m 1 m 2 m 3...m p−2 m p−1), allowing the representation of numbers closer to zero than the smallest normal number. A floating-point number may be recognized as subnormal whenever its exponent has the least possible value.
largest subnormal number 0 00001 0000000000: 0400: 2 −14 × (1 + 0 / 1024 ) ≈ 0.00006103515625: smallest positive normal number 0 01101 0101010101: 3555: 2 −2 × (1 + 341 / 1024 ) ≈ 0.33325195: nearest value to 1/3 0 01110 1111111111: 3bff: 2 −1 × (1 + 1023 / 1024 ) ≈ 0.99951172: largest number less than one 0 ...
In computing, NaN (/ n æ n /), standing for Not a Number, is a particular value of a numeric data type (often a floating-point number) which is undefined as a number, such as the result of 0/0. Systematic use of NaNs was introduced by the IEEE 754 floating-point standard in 1985, along with the representation of other non-finite quantities ...
The numerical value of such a finite number is (−1) s × c × b q. [a] Moreover, there are two zero values, called signed zeros: the sign bit specifies whether a zero is +0 (positive zero) or −0 (negative zero). Two infinities: +∞ and −∞. Two kinds of NaN (not-a-number): a quiet NaN (qNaN) and a signaling NaN (sNaN).
[3]: 19-- It does not require computing the topological degree; it only requires computing the signs of function values. The number of required evaluations is at least log 2 ( D / ϵ ) {\displaystyle \log _{2}(D/\epsilon )} , where D is the length of the longest edge of the characteristic polyhedron.
The exponent field is an 8-bit unsigned integer from 0 to 255, in biased form: a value of 127 represents the actual exponent zero. Exponents range from −126 to +127 (thus 1 to 254 in the exponent field), because the biased exponent values 0 (all 0s) and 255 (all 1s) are reserved for special numbers ( subnormal numbers , signed zeros ...
7f7f = 0 11111110 1111111 = (2 8 − 1) × 2 −7 × 2 127 ≈ 3.38953139 × 10 38 (max finite positive value in bfloat16 precision) 0080 = 0 00000001 0000000 = 2 −126 ≈ 1.175494351 × 10 −38 (min normalized positive value in bfloat16 precision and single-precision floating point)
The minimum strictly positive (subnormal) value is 2 −16494 ≈ 10 −4965 and has a precision of only one bit. The minimum positive normal value is 2 −16382 ≈ 3.3621 × 10 −4932 and has a precision of 113 bits, i.e. ±2 −16494 as well. The maximum representable value is 2 16384 − 2 16271 ≈ 1.1897 × 10 4932.