Search results
Results from the WOW.Com Content Network
The Marshall-Edgeworth index, credited to Marshall (1887) and Edgeworth (1925), [11] is a weighted relative of current period to base period sets of prices. This index uses the arithmetic average of the current and based period quantities for weighting. It is considered a pseudo-superlative formula and is symmetric. [12]
In contrast to a cost-of-living index based on the true but unknown utility function, a superlative index number is an index number that can be calculated. [1] Thus, superlative index numbers are used to provide a fairly close approximation to the underlying cost-of-living index number in a wide range of circumstances. [1] Some indexes are not ...
Functions of a single variable (such as sine and cosine) may be implemented by a simple array. Functions involving two or more variables require multidimensional array indexing techniques. The latter case may thus employ a two-dimensional array of power[x][y] to replace a function to calculate x y for a limited range of x and y values ...
The number of relevant documents, , is used as the cutoff for calculation, and this varies from query to query. For example, if there are 15 documents relevant to "red" in a corpus (R=15), R-precision for "red" looks at the top 15 documents returned, counts the number that are relevant r {\\displaystyle r} turns that into a relevancy fraction ...
to access the same element, which arguably looks more complicated. Of course, r′ = r + 1, since [z = z′ – 1], [y = y′ – 1], and [x = x′ – 1]. A simple and everyday-life example is positional notation, which the invention of the zero made possible. In positional notation, tens, hundreds, thousands and all other digits start with ...
If this number is odd, then U=2L and one of the new nodes contains (U−2)/2 = L−1 elements, and hence is a legal node, and the other contains one more element, and hence it is legal too. If U−1 is even, then U=2L−1, so there are 2L−2 elements in the node. Half of this number is L−1, which is the minimum number of elements allowed per ...
Upgrade to a faster, more secure version of a supported browser. It's free and it only takes a few moments:
function lookupByPositionIndex(i) node ← head i ← i + 1 # don't count the head as a step for level from top to bottom do while i ≥ node.width[level] do # if next step is not too far i ← i - node.width[level] # subtract the current width node ← node.next[level] # traverse forward at the current level repeat repeat return node.value end ...