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At 20 °C and 101.325 kPa, dry air has a density of 1.2041 kg/m 3. At 70 °F and 14.696 psi, dry air has a density of 0.074887 lb/ft 3. The following table illustrates the air density–temperature relationship at 1 atm or 101.325 kPa: [citation needed]
Density system unit unit-code symbol or abbrev. notes sample default conversion combination output units Metric: kilogram per cubic metre: kg/m3 kg/m 3: 1.0 kg/m 3 (1.7 lb/cu yd) kg/m3 lb/ft3 (kg/m3 lb/cuft) kg/m3 lb/yd3 (kg/m3 lb/cuyd) gram per cubic metre: g/m3 g/m 3: 1.0 g/m 3 (0.0017 lb/cu yd) g/m3 kg/m3; g/m3 lb/ft3 (g/cm3 lb/cuft) g/m3 lb ...
— "Values ranging from 21.3 to 21.5 gm/cm 3 at 20 °C have been reported for the density of annealed platinum; the best value being about 21.45 gm/cm 3 at 20 °C." 21.46 g/cm 3 — Rose, T. Kirke. The Precious Metals, Comprising Gold, Silver and Platinum .
Density system unit unit-code symbol or abbrev. notes sample default conversion combination output units Metric: kilogram per cubic metre: kg/m3 kg/m 3: 1.0 kg/m 3 (1.7 lb/cu yd)
using Plots # Saturated water vapor pressure [Pa] # See Ham, 2005. Useful Equations and Tables in Micrometeorology function water_vapor_saturated_pressure (Ta, P) Ta = Ta-273.15 es = (1.0007 + (3.46e-5 * (P / 1e3))) * 0.61121 * exp ((17.502 * Ta) / (Ta + 240.97)) * 1e3 return es end function water_vapor_density (e, Tair) Rs_v = 461.5 # J/(kg.K) specific gas constant for water vapor ρv = e ...
at each geopotential altitude, where g is the standard acceleration of gravity, and R specific is the specific gas constant for dry air (287.0528J⋅kg −1 ⋅K −1). The solution is given by the barometric formula. Air density must be calculated in order to solve for the pressure, and is used in calculating dynamic pressure for moving vehicles.
Composition of dry atmosphere, by volume [ note 1] [ note 2]; Gas (and others): Various [1]: CIPM-2007 [2]: ASHRAE [3]: Schlatter [4]: ICAO [5]: US StdAtm76 [6]: Tap ...
Since the density of dry air at 101.325 kPa at 20 °C is [9] 0.001205 g/cm 3 and that of water is 0.998203 g/cm 3 we see that the difference between true and apparent relative densities for a substance with relative density (20 °C/20 °C) of about 1.100 would be 0.000120. Where the relative density of the sample is close to that of water (for ...