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  2. How do you simplify the Square root of 48? - Socratic

    socratic.org/questions/how-do-you-simplify-the-square-root-of-48

    In cases like this you factorise the 48 and see if you can find any squares to be taken out from under the root. 48=16*3=4^2*3-> sqrt48=sqrt(4^2*3)=sqrt(4^2)*sqrt3=4sqrt3

  3. How do you simplify #sqrt(48)#? - Socratic

    socratic.org/questions/how-do-you-simplify-sqrt-48

    To simplify √48, we should first factorize 48. As 2 is one factor, dividing 48 by 2, we get 24, which has factors 2 again. This way we go on till we get all the factors. Hence √48 = √2 × 2 × 2 × 2 × 3. As 2 has appeared four times, square root of 2 ×2 ×2 ×2 will be just 2 ×2. Note we cannot take square root of 3 as it has not ...

  4. How do you simplify #sqrt(48) + sqrt(108)#? - Socratic

    socratic.org/questions/how-do-you-simplify-sqrt-48-sqrt-108

    #48=4^2xx3# #108=6^2xx3# #sqrt(48)+sqrt(108)# #color(white)("XXX")=sqrt(4^2xx3)+sqrt(6^2xx3)# #color(white)("XXX")=4sqrt(3)+6sqrt(3)#

  5. How you simplify (Square root of 75) +(square root of 48)? -...

    socratic.org/questions/how-you-simplify-square-root-of-75-square-root-of-48

    Explanation: Square root of a number can be simplified by prime factorising the number. Prime factorisation involves expressing a number as a product of prime numbers. (75 has 3 and 5 as its prime factors and 48 has 2 and 3 as its prime factors) So, √75 = √5 ⋅ 5 ⋅ 3 = √52 ⋅ 3 = 5√3. √48 = √2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 = √22 ⋅ ...

  6. Simplification of Radical Expressions - Algebra - Socratic

    socratic.org/algebra/radicals-and-geometry-connections/simplification-of...

    There are two common ways to simplify radical expressions, depending on the denominator. Using the identities \sqrt {a}^2=a and (a-b) (a+b)=a^2-b^2, in fact, you can get rid of the roots at the denominator. Case 1: the denominator consists of a single root. For example, let's say that our fraction is {3x}/ {\sqrt {x+3}}.

  7. What is the simplified square root of 48? - Socratic

    socratic.org/questions/what-is-the-simplified-square-root-of-48

    I think you can write it as (remembering that sqrt(4)=2): sqrt(48)=sqrt(6*4*2)=2sqrt(6*2)=2sqrt(3*2*2)=2sqrt(3*4)=4sqrt(3)

  8. What is the square root of 48/27? - Socratic

    socratic.org/questions/what-is-the-square-root-of-48-27

    You have: #sqrt(48/27)=sqrt((cancel(6)^2*8)/(cancel(3)*9))=sqrt(16/9)=4/3# Answer link. Related questions

  9. How would I simplify square root 48+square root 27? - Socratic

    socratic.org/questions/how-would-i-simplify-square-root-48-square-root-27

    First try and get some squares out of the root 48=4^2*3->sqrt48=sqrt(4^2)*sqrt3=4sqrt3 27=3^2*3->sqrt27 ...

  10. SOLUTION: Simplify. square root of 48/75 Be sure to write your...

    www.algebra.com/algebra/homework/NumericFractions/Numeric_Fractions.faq...

    Answer by Wew12345 (1) ( Show Source ): You can put this solution on YOUR website! 48/75 is equals to n. find the greatest common factor (GCF) the GCF is 3. 48 / 3 is 16. 75 / 3 is 25. the answer in lowest term is 16/25.

  11. SOLUTION: Simplify the Square root of 48 divided by square root...

    www.algebra.com/algebra/homework/Square-cubic-other-roots/Square-cubic-other...

    Click here to see ALL problems on Square-cubic-other-roots. Question 602402: Simplify the Square root of 48 divided by square root of 147. Answer by ewatrrr (24785) ( Show Source ): You can put this solution on YOUR website! Hi, Simplify the Square root of 48 divided by square root of 147. Note: Expressing Numerator and Denominator in terms of.