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days, hours, minutes = td.days, td.seconds // 3600, td.seconds // 60 % 60 As for DST, I think the best thing is to convert both datetime objects to seconds. This way the system calculates DST for you.
def convert_timedelta(duration): days, seconds = duration.days, duration.seconds hours = seconds // 3600 minutes = (seconds % 3600) // 60 seconds = (seconds % 60) return days, hours, minutes, seconds If you want to convert this to a single value to store in a database, then convert that single value back to format it, do this:
Using datetime example >>> from datetime import datetime >>> then = datetime(2012, 3, 5, 23, 8, 15) # Random date in the past >>> now = datetime.now() # Now ...
I have an output of minutes that I'd like to convert to days, hours, and minutes using excel. I haven't been able to find this conversion. Ex. 1610 minutes, would equal 1 day, 2 hours and 50 mins. The number in the field is 1610. Is that a formula I can use to convert the number 1610 to return the number of day, hours and minutes? Thank you
As you can see the timedelta 0:15:00 which it means for 15 minutes so I want to convert it to 15, for 0:35:00 as 35 minutes I want to convert it to 35, for 0:45:00 as 45 minutes I want to convert it to 45, but for 2:00:00 as 2 hours I want to convert it to 120 as 120 minutes. For 1:30:00 as 1 hour and 30 minutes I want to convert it to 90 minutes.
How do I calculate the difference in time in minutes for the following timestamp in Python? 2010-01-01 17:31:22 2010-01-03 17:31:22
With what I have it isn't giving me the remaining minutes into days. For example, if I put in 525600 minutes it gives me 1 year and 365 days when it should just be 1 year. I'm using Java Eclipse. Any help would be greatly appreciated! My apologies in advance if I post the code incorrectly.
somehow if you add 29 days to current date - then the diff is 28 days, 23 hours 59 minutes 59 seconds, but if you add 30 days, then the diff is 30 days, 0 hours 59 minutes 59 seconds. I.e. one extra hour is added. Something is wrong with this and the other answers..
In [17]: s.dt.components Out[17]: days hours minutes seconds milliseconds microseconds nanoseconds 0 1 0 0 0 0 0 0 1 3 2 0 0 0 0 0 2 5 4 0 0 0 0 0 3 7 6 0 0 0 0 0 4 9 8 0 0 0 0 0 5 11 10 0 0 0 0 0 Now, to get the hours attribute:
Output: 2 days, 10 hours, 5 minutes and 21 seconds. Share. Improve this answer. Follow