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4), the perceived energy capacity of a small UPS product that has multiple DC outputs at different voltages but is simply listed with a single ampere-hour rating, e.g., 8800 mAh, would be exaggerated by a factor of 3.75 compared to that of a sealed 12-volt lead-acid battery where the ampere-hour rating, e.g., 7 Ah, is based on the total output ...
The difference in electric potential across two points along a conducting wire carrying one ampere of constant current when the power dissipated between the points equals one watt. [ 32 ] = 1 V = 1 W/A = 1 kg⋅m 2 /(A⋅s 3 ) = 1 J/C
1 terawatt hour per year = 1 × 10 12 W·h / (365 days × 24 hours per day) ≈ 114 million watts, equivalent to approximately 114 megawatts of constant power output. The watt-second is a unit of energy, equal to the joule. One kilowatt hour is 3,600,000 watt seconds.
The NIST document gives conversion factors correct to 7 places. Factors in bold are exact. If exact factors have more than 7 places, they are rounded and no longer exact. This convert module replaces these rounded figures with the exact figures. For example, the NIST document has 1 square mile = 2.589 988 E+06 square meters.
Conversion of units is the conversion of the unit of measurement in which a quantity is expressed, typically through a multiplicative conversion factor that changes the unit without changing the quantity. This is also often loosely taken to include replacement of a quantity with a corresponding quantity that describes the same physical property.
The power factor in a single-phase circuit (or balanced three-phase circuit) can be measured with the wattmeter-ammeter-voltmeter method, where the power in watts is divided by the product of measured voltage and current. The power factor of a balanced polyphase circuit is the same as that of any phase. The power factor of an unbalanced ...
Using the above example, if a battery rated for 100 ampere-hours at a 20-hour rate has a Peukert constant of 1.2 and is discharged at a rate of 10 amperes, it would be fully discharged in time (), which is approximately 8.7 hours. It would therefore deliver only 87 ampere-hours rather than 100.
Equipment data sheets and nameplates will often abbreviate power factor as "" for this reason. Example: The active power is 700 W and the phase angle between voltage and current is 45.6°. The power factor is cos(45.6°) = 0.700. The apparent power is then: 700 W / cos(45.6°) = 1000 VA. The concept of power dissipation in AC circuit is ...