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Although the classic substrate for the Criegee oxidation are 1,2-diols, the oxidation can be employed with β-amino alcohols, [10] α-hydroxy carbonyls, [11] and α-keto acids, [12] In the case of β-amino alcohols, a free radical mechanism is proposed. The Criegee oxidation can also be employed with 2,3-epoxy alcohols forms α-acetoxy carbonyls.
1.54 g/cm 3: Melting point: α-d-Glucose: 146 °C ... to occur experimentally via oxidation and hydrolysis at 22 °C and a pH of 2.5. ... specifically to the 1,2-diol ...
Propylene glycol (IUPAC name: propane-1,2-diol) is a viscous, colorless liquid. It is almost odorless and has a faintly sweet taste. Its chemical formula is CH 3 CH(OH)CH 2 OH. As it contains two alcohol groups, it is classified as a diol. An aliphatic diol may also be called a glycol.
1,2-Butanediol is a byproduct of the production of 1,4-butanediol from butadiene. [8] It is also a byproduct of the catalytic hydrocracking of starches and sugars such as sorbitol to ethylene glycol and propylene glycol. [9] It can also be obtained from the dihydroxylation of but-1-ene by OsO 4.
Ethylene glycol (IUPAC name: ethane-1,2-diol) is an organic compound (a vicinal diol [7]) with the formula (CH 2 OH) 2. It is mainly used for two purposes: as a raw material in the manufacture of polyester fibers and for antifreeze formulations. It is an odorless, colorless, flammable, viscous liquid.
In a vicinal diol, the two hydroxyl groups occupy vicinal positions, that is, they are attached to adjacent atoms. These compounds are called glycols [5] (though the term can be used more widely). Examples include ethane-1,2-diol or ethylene glycol HO−(CH 2) 2 −OH, a common ingredient of antifreeze products.
2-methylpropane-1,2-diol; 2-methylpropane-1,3-diol; and one unstable geminal diol: 2-methylpropane-1,1-diol (not a glycol), hydrate of 2-methylpropanal (isobutyraldehyde) These three methylpropanediols are structural isomers of butanediols. They are not chiral.
The standard hydrogen electrode (SHE), with [ H +] = 1 M works thus at a pH = 0. At pH = 7, when [ H +] = 10 −7 M, the reduction potential of H + differs from zero because it depends on pH. Solving the Nernst equation for the half-reaction of reduction of two protons into hydrogen gas gives: 2 H + + 2 e − ⇌ H 2