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calorie: Cal (Calorie) Cal 1.0 Cal (4.2 kJ) megacalorie: Mcal Mcal 1.0 Mcal (4.2 MJ) kilocalorie: kcal kcal 1.0 kcal (4.2 kJ) calorie: cal cal 1.0 cal (4.2 J) millicalorie ...
Download as PDF; Printable version; ... Cal-th (kg-cal-th) Cal th: 1.0 Cal th (4.2 ... (g-cal-15) kcal 15: 1.0 kcal 15 (4.2 ...
the small calorie (gram-calorie, cal) is 4.184 J exactly. It was originally defined so that the specific heat capacity of liquid water would be 1 cal/(°C⋅g). The grand calorie (kilocalorie, kilogram-calorie, food calorie, kcal, Cal) is 1000 small calories, 4184 J exactly. It was defined so that the specific heat capacity of water would be 1 ...
The amount of energy equal to exactly 4.184 J and 1 kJ ≈ 0.239 kcal. [18] [19] [20] [11] [a] 4 °C calorie: cal 4: ≈ 4.204 J ≈ 0.003 985 BTU ≈ 1.168 × 10 −6 kW⋅h ≈ 2.624 × 10 19 eV The amount of energy required to warm one gram of air-free water from 3.5 to 4.5 °C at standard atmospheric pressure. [b] 15 °C calorie: cal 15
The contribution of the muscle to the specific heat of the body is approximately 47%, and the contribution of the fat and skin is approximately 24%. The specific heat of tissues range from ~0.7 kJ · kg−1 · °C−1 for tooth (enamel) to 4.2 kJ · kg−1 · °C−1 for eye (sclera). [13]
Energy density is thus commonly expressed in metric units of cal/g, kcal/g, J/g, kJ/g, MJ/kg, cal/mL, kcal/mL, J/mL, or kJ/mL. Energy density measures the energy released when the food is metabolized by a healthy organism when it ingests the food (see food energy for calculation).
The "grand calorie" (also "kilocalorie", "kilogram-calorie", or "food calorie"; "kcal" or "Cal") is 1000 cal, that is, exactly 4184 J. It was originally defined so that the heat capacity of 1 kg of water would be 1 kcal/°C. With these units of heat energy, the units of heat capacity are 1 cal/°C = 4.184 J/K ; 1 kcal/°C = 4184 J/K.
We can treat these two processes independently and using the specific heat capacity of water to be 4.18 J/(g⋅K); thus, to heat 1 kg of ice from 273.15 K to water at 293.15 K (0 °C to 20 °C) requires: (1) 333.55 J/g (heat of fusion of ice) = 333.55 kJ/kg = 333.55 kJ for 1 kg of ice to melt, plus (2) 4.18 J/(g⋅K) × 20 K = 4.18 kJ/(kg⋅K ...