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One method of preparing red phosphorus involves heating white phosphorus in an inert atmosphere like nitrogen or carbon dioxide, with iodine as catalyst. [4]Another theoretically possible method of red phosphorus production is via light irradiation of white phosphorus. [5]
Red phosphorus. Red phosphorus may be formed by heating white phosphorus to 300 °C (570 °F) in the absence of air or by exposing white phosphorus to sunlight. Red phosphorus exists as an amorphous network. Upon further heating, the amorphous red phosphorus crystallizes. It has two crystalline forms: violet phosphorus and fibrous red ...
Elemental phosphorus exists in two major forms, white phosphorus and red phosphorus, but because it is highly reactive, phosphorus is never found as a free element on Earth. It has a concentration in the Earth's crust of about 0.1%, less abundant than hydrogen but more than manganese .
Copper phosphide can be produced in a reverberatory furnace or in a crucible, e.g. by a reaction of red phosphorus with a copper-rich material. It can also be prepared photochemically, by irradiating cupric hypophosphite with ultraviolet radiation. [5] It can also be produced by reducing copper(II) phosphate with aluminum. [6]
Lead heptaphosphide is the only binary phosphide currently known to be formed by lead and phosphorus. The chemical formula is PbP 7 , which contains [P 7 ] 2− atom clusters. This compound is stable in the air.
The development of color TV took a long time due to the search for a red phosphor. The first red emitting rare-earth phosphor, YVO 4:Eu 3+, was introduced by Levine and Palilla as a primary color in television in 1964. [29] In single crystal form, it was used as an excellent polarizer and laser material. [30]
Heating powdered europium and red phosphorus in an inert atmosphere or vacuum: [citation needed] 4 Eu + P 4 → 4 EuP. Passing phosphine through a solution of europium in liquid ammonia: [6] Eu + 2PH 3 → Eu(PH 2) 2 + H 2. Eu(PH 2) 2 is formed, which then decomposes to europium(III) phosphide and phosphine: [6] [7] 2Eu(PH 2) 2 → 2EuP + 2PH 3 ...
When a halide atom is found in the ester chain off of the phosphorus atom, isomerization to the corresponding Arbuzov product has been known without addition of an alkyl halide. The Perkow reaction is a competing reaction pathway for α-bromo- and α-chloroketones. Under the reaction conditions a mixture of the Perkow product and the normal ...