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The heating value depends on the source of gas that is used and the process that is used to liquefy the gas. The range of heating value can span ±10 to 15 percent. A typical value of the higher heating value of LNG is approximately 50 MJ/kg or 21,500 BTU/lb. [2] A typical value of the lower heating value of LNG is 45 MJ/kg or 19,350 BTU/lb.
Many gases can be put into a liquid state at normal atmospheric pressure by simple cooling; a few, such as carbon dioxide, require pressurization as well. Liquefaction is used for analyzing the fundamental properties of gas molecules (intermolecular forces), or for the storage of gases, for example: LPG , and in refrigeration and air conditioning .
A log-lin vapor pressure chart for various liquids. The higher the vapor pressure of a liquid at a given temperature, the lower the normal boiling point (i.e., the boiling point at atmospheric pressure) of the liquid. The vapor pressure chart to the right has graphs of the vapor pressures versus temperatures for a variety of liquids. [10]
Boiling-point diagram. The preceding equilibrium equations are typically applied for each phase (liquid or vapor) individually, but the result can be plotted in a single diagram. In a binary boiling-point diagram, temperature (T ) (or sometimes pressure) is graphed vs. x 1. At any given temperature (or pressure) where both phases are present ...
LNG: 332.7 WEL: 318 Zhang et al. 310 22 Ti titanium; use: 425 LNG: 425 WEL: 425 Zhang et al. 427 23 V vanadium; use: 444 LNG: 459 WEL: 453 Zhang et al. 451 24 Cr chromium; use: 339.5 LNG: 339.5 WEL: 339 Zhang et al. 347 25 Mn manganese; use: 221 LNG: 221 WEL: 220 Zhang et al. 225 26 Fe iron; use: 340 LNG: 340 WEL: 347 Zhang et al. 354 27 Co ...
Compressibility factor values are usually obtained by calculation from equations of state (EOS), such as the virial equation which take compound-specific empirical constants as input. For a gas that is a mixture of two or more pure gases (air or natural gas, for example), the gas composition must be known before compressibility can be calculated.
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The correct result would be P = 101.325 kPa, the normal (atmospheric) pressure. The deviation is −1.63 kPa or −1.61 %. The deviation is −1.63 kPa or −1.61 %. It is important to use the same absolute units for T and T c as well as for P and P c .