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2. The Three Basic Rules of Operator Overloading in C++ - Stack...

   stackoverflow.com/.../what-are-the-basic-rules-and-idioms-for-operator-overloading

   The Three Basic Rules of Operator Overloading in C++. When it comes to operator overloading in C++, there are three basic rules you should follow. As with all such rules, there are indeed exceptions. Sometimes people have deviated from them and the outcome was not bad code, but such positive deviations are few and far between.

3. c++ - How can I properly overload the << operator for an ostream...

   stackoverflow.com/questions/476272

   I would like to simplify this a little with an example that overloads << to print an array. First pass both the object types around the << operator. Create a function to overload the operator as follows. #include <iostream>. using namespace std; void operator<<(ostream& os, int arr[]) {. for (int i = 0;i < 10; i++) {.

4. c++ - >> and << operator overloading - Stack Overflow

   stackoverflow.com/questions/4066666

   BigInt operator << (const BigInt &i, unsigned int shift); To expand this a bit further, the original use of the << operator is for bit shifting. 1 << 8 is 256, for example. C++ added a (slightly confusing) second use for this, and overloaded it on ostream to mean "output" to the stream. You can do whatever you like within an overloaded operator ...

5. c++ - What's the right way to overload operator== for a class...

   stackoverflow.com/questions/1691007

   1. This is a classical double dispatch problem. Either your hierarchy is known ahead of time, in which case you must write n * (n - 1) / 2 functions, or it is not and you must find another way (eg. return a hash of the object and compare hashes). – Alexandre C. Feb 1, 2013 at 19:06.

6. C++ -- How to overload operator+=? - Stack Overflow

   stackoverflow.com/questions/4581961

   Class& operator @= (const Class& rhs); That is, the function takes its parameter by const reference (because it doesn't modify it), then returns a mutable reference to the object. The reason you return a non-const reference is because, for historical reasons, you can write code like this: (a += b) += c; This is by no means good style, but it ...

7. C++ operator== overloading - Stack Overflow

   stackoverflow.com/questions/10070020

   bool MyClass::operator== (MyClass &rhs); You should use second variant always then you can. You should use first variant in case: 1) First argument is the external (library) class. friend ostream& operator<< (ostream &out, MyClass &m) 2) Operator's logic not related to your class and must be implemented separately.

8. C++ Operator () parenthesis overloading - Stack Overflow

   stackoverflow.com/questions/5503438

   return entry.getHost() == blockedHost || entry.getHost() == "www." + blockedHost; const std::string& blockedHost; to be used as: I looked at std::remove_if's documentation, it says that it is possible to pass a class instead of a function only when the class overloads the () operator. No information whatsoever.

9. c++ - Operator Overloading in struct - Stack Overflow

   stackoverflow.com/questions/13480135

   In C++ there's only one difference between a struct and a class: in a struct the default visibility is public while in a class it is private. Other than that you can do anything you would do in a class in a struct and it will look exactly the same. Write operator overloading in a struct as you would in a class. answered Nov 20, 2012 at 18:58.

10. Overloaded Addition assignment operator in C++ for two /more than...

    stackoverflow.com/questions/11161541

    Using friend operator overload should do the trick for you and is a common way to define binary operators, just add: friend sample operator+(const sample& a, const sample& b); //in class sample operator+(const sample& a, const sample& b) { //outside the class return sample(a.x + b.x); }

11. simple c++: How to overload the multiplication operator so that...

    stackoverflow.com/questions/10354886

    It works - the operator is scoped to the object to which it is declared. In the first case, the subtlety is that the functions are not member functions of MyClass, they are at global scope - and argument-dependent lookup will find them even if the first argument is a float.