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IEEE 802.11n (aka Wi-Fi 4) 600 Mbit/s: 75 MB/s: 2009 IEEE 802.11ac (aka Wi-Fi 5) 6.8–6.93 Gbit/s: 850–866.25 MB/s: 2012 IEEE 802.11ad: 7.14–7.2 Gbit/s: 892.5–900 MB/s: 2011 IEEE 802.11ax (aka Wi-Fi 6/6E) 11 Gbit/s: 1.375 GB/s: 2019 IEEE 802.11be (aka Wi-Fi 7 or Extremely High Throughput (EHT)) 46.12 Gbit/s expected: 5.765 GB/s expected ...
The ISQ symbols for the bit and byte are bit and B, respectively.In the context of data-rate units, one byte consists of 8 bits, and is synonymous with the unit octet.The abbreviation bps is often used to mean bit/s, so that when a 1 Mbps connection is advertised, it usually means that the maximum achievable bandwidth is 1 Mbit/s (one million bits per second), which is 0.125 MB/s (megabyte per ...
In telecommunications and computing, bit rate (bitrate or as a variable R) is the number of bits that are conveyed or processed per unit of time. [1]The bit rate is expressed in the unit bit per second (symbol: bit/s), often in conjunction with an SI prefix such as kilo (1 kbit/s = 1,000 bit/s), mega (1 Mbit/s = 1,000 kbit/s), giga (1 Gbit/s = 1,000 Mbit/s) or tera (1 Tbit/s = 1,000 Gbit/s). [2]
Throughput is usually measured in bits per second (bit/s, sometimes abbreviated bps), and sometimes in packets per second (p/s or pps) or data packets per time slot. The system throughput or aggregate throughput is the sum of the data rates that are delivered over all channels in a network. [ 1 ]
The link spectral efficiency of a digital communication system is measured in bit/s/Hz, [2] or, less frequently but unambiguously, in (bit/s)/Hz.It is the net bit rate (useful information rate excluding error-correcting codes) or maximum throughput divided by the bandwidth in hertz of a communication channel or a data link.
In actuality, a 64 kilobyte file is 64 × 1,024 × 8 bits in size and the 64 k circuit will transmit bits at a rate of 64 × 1,000 bit/s, so the amount of time taken to transmit a 64 kilobyte file over the 64 k circuit will be at least (64 × 1,024 × 8)/(64 × 1,000) seconds, which works out to be 8.192 seconds.
In order to calculate the data transmission rate, one must multiply the transfer rate by the information channel width. For example, a data bus eight-bytes wide (64 bits) by definition transfers eight bytes in each transfer operation; at a transfer rate of 1 GT/s, the data rate would be 8 × 10 9 B/s, i.e. 8 GB/s, or approximately 7.45 GiB/s
The packet transmission time in seconds can be obtained from the packet size in bit and the bit rate in bit/s as: Packet transmission time = Packet size / Bit rate. Example: Assuming 100 Mbit/s Ethernet, and the maximum packet size of 1526 bytes, results in Maximum packet transmission time = 1526×8 bit / (100 × 10 6 bit/s) ≈ 122 μs