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  2. Fermat number - Wikipedia

    en.wikipedia.org/wiki/Fermat_number

    The Fermat numbers satisfy the following recurrence relations: = + = + for n ≥ 1, = + = for n ≥ 2.Each of these relations can be proved by mathematical induction.From the second equation, we can deduce Goldbach's theorem (named after Christian Goldbach): no two Fermat numbers share a common integer factor greater than 1.

  3. Fermat's factorization method - Wikipedia

    en.wikipedia.org/wiki/Fermat's_factorization_method

    Fermat's factorization method, named after Pierre de Fermat, is based on the representation of an odd integer as the difference of two squares: N = a 2 − b 2 . {\displaystyle N=a^{2}-b^{2}.} That difference is algebraically factorable as ( a + b ) ( a − b ) {\displaystyle (a+b)(a-b)} ; if neither factor equals one, it is a proper ...

  4. Factorization - Wikipedia

    en.wikipedia.org/wiki/Factorization

    Typically, one may proceed by testing 2, 3, 5, and the numbers > 5, whose last digit is 1, 3, 7, 9 and the sum of digits is not a multiple of 3. This method works well for factoring small integers, but is inefficient for larger integers. For example, Pierre de Fermat was unable to discover that the 6th Fermat number

  5. Cunningham Project - Wikipedia

    en.wikipedia.org/wiki/Cunningham_Project

    Cunningham numbers of the form b n − 1 can only be prime if b = 2 and n is prime, assuming that n ≥ 2; these are the Mersenne numbers. Numbers of the form b n + 1 can only be prime if b is even and n is a power of 2, again assuming n ≥ 2; these are the generalized Fermat numbers, which are Fermat numbers when b = 2.

  6. Fermat pseudoprime - Wikipedia

    en.wikipedia.org/wiki/Fermat_pseudoprime

    When p is a prime, p 2 is a Fermat pseudoprime to base b if and only if p is a Wieferich prime to base b. For example, 1093 2 = 1194649 is a Fermat pseudoprime to base 2, and 11 2 = 121 is a Fermat pseudoprime to base 3. The number of the values of b for n are (For n prime, the number of the values of b must be n − 1, since all b satisfy the ...

  7. Pépin's test - Wikipedia

    en.wikipedia.org/wiki/Pépin's_test

    For integer b > 1, base b may be used if and only if only a finite number of Fermat numbers F n satisfies that () =, where () is the Jacobi symbol. In fact, Pépin's test is the same as the Euler-Jacobi test for Fermat numbers, since the Jacobi symbol ( b F n ) {\displaystyle \left({\frac {b}{F_{n}}}\right)} is −1, i.e. there are no Fermat ...

  8. Fermat primality test - Wikipedia

    en.wikipedia.org/wiki/Fermat_primality_test

    For these numbers, repeated application of the Fermat primality test performs the same as a simple random search for factors. While Carmichael numbers are substantially rarer than prime numbers (Erdös' upper bound for the number of Carmichael numbers [ 3 ] is lower than the prime number function n/log(n) ) there are enough of them that Fermat ...

  9. Proofs of Fermat's little theorem - Wikipedia

    en.wikipedia.org/wiki/Proofs_of_Fermat's_little...

    Some of the proofs of Fermat's little theorem given below depend on two simplifications.. The first is that we may assume that a is in the range 0 ≤ a ≤ p − 1.This is a simple consequence of the laws of modular arithmetic; we are simply saying that we may first reduce a modulo p.

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