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2. Getting random numbers in Java - Stack Overflow

   stackoverflow.com/questions/5887709

   The first solution is to use the java.util.Random class: import java.util.Random; Random rand = new Random(); // Obtain a number between [0 - 49]. int n = rand.nextInt(50); // Add 1 to the result to get a number from the required range // (i.e., [1 - 50]). n += 1; Another solution is using Math.random(): double random = Math.random() * 49 + 1 ...

3. How do I generate random integers within a specific range in Java...

   stackoverflow.com/questions/363681

   To generate a random number "in between two numbers", use the following code: Random r = new Random(); int lowerBound = 1; int upperBound = 11; int result = r.nextInt(upperBound-lowerBound) + lowerBound; This gives you a random number in between 1 (inclusive) and 11 (exclusive), so initialize the upperBound value by adding 1.

4. True random generation in Java - Stack Overflow

   stackoverflow.com/questions/381037

   The NSA and Intel’s Hardware Random Number Generator. To make things easier for developers and help generate secure random numbers, Intel chips include a hardware-based random number generator known as RdRand. This chip uses an entropy source on the processor and provides random numbers to software when the software requests them.

5. Generating Unique Random Numbers in Java - Stack Overflow

   stackoverflow.com/questions/8115722

   With Java 8+ you can use the ints method of Random to get an IntStream of random values then distinct and limit to reduce the stream to a number of unique random values. ThreadLocalRandom.current().ints(0, 100).distinct().limit(5).forEach(System.out::println);

6. Java random number with given length - Stack Overflow

   stackoverflow.com/questions/5392693

   To generate a 6-digit number: Use Random and nextInt as follows: Random rnd = new Random(); int n = 100000 + rnd.nextInt(900000); Note that n will never be 7 digits (1000000) since nextInt(900000) can at most return 899999. So how do I randomize the last 5 chars that can be either A-Z or 0-9? Here's a simple solution:

7. Generating a Random Number between 1 and 10 Java

   stackoverflow.com/questions/20389890

   import java.util.Random; If you want to test it out try something like this. Random rn = new Random(); for(int i =0; i < 100; i++) { int answer = rn.nextInt(10) + 1; System.out.println(answer); } Also if you change the number in parenthesis it will create a random number from 0 to that number -1 (unless you add one of course like you have then ...

8. Java Generate Random Number Between Two Given Values

   stackoverflow.com/questions/5271598

   The first (100) is the number I am ADDING to the random one. This means that the new output number will be the random number + 100. numGen.nextInt() is the value of the random number itself, and because I put (100) in its parentheses, it is any number between 1 and 100. So when I add 100, it becomes a number between 101 and 200.

9. Java random numbers using a seed - Stack Overflow

   stackoverflow.com/questions/12458383

   Pseudorandom number generator. A pseudorandom number generator (PRNG), also known as a deterministic random bit generator DRBG, is an algorithm for generating a sequence of numbers that approximates the properties of random numbers.

10. java - How to generate a random alpha-numeric string - Stack...

    stackoverflow.com/questions/41107

    To get a random character containing all digits 0-9 and characters a-z, we would need a random number between 0 and 35 to get one of each character. BigInteger provides a constructor to generate a random number, uniformly distributed over the range 0 to (2^numBits - 1). Unfortunately 35 is not a number which can be received by 2^numBits - 1.

11. java - Generate 6 digit random number - Stack Overflow

    stackoverflow.com/questions/51322750

    this will return your number in string format, so the "0" will be "000000". Here is the code. public static String getRandomNumberString() { // It will generate 6 digit random Number. // from 0 to 999999 Random rnd = new Random(); int number = rnd.nextInt(999999); // this will convert any number sequence into 6 character.