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In baseball statistics, exit velocity (EV) is the estimated speed at which a batted ball is travelling as it is coming off the player's bat. Batters generally aim for a higher exit velocity in order to give opposing fielders less time to react and attempt a defensive play; however, many batters are still able to accrue hits without a high exit ...
Escape speed at a distance d from the center of a spherically symmetric primary body (such as a star or a planet) with mass M is given by the formula [2] [3] = = where: G is the universal gravitational constant (G ≈ 6.67×10 −11 m 3 ·kg −1 ·s −2)
On August 9, 2018, in a game against the Texas Rangers, Stanton hit a home run with an exit velocity of 121.7 miles per hour (195.9 km/h), the fastest exit velocity for a home run measured by Statcast, surpassing the previous record of 121.1 miles per hour (194.9 km/h) held by Aaron Judge. [24]
The gas accelerates to a final exit velocity which depends on the pressure and temperature at entry to the nozzle, the ambient pressure it exhausts to (unless the flow is choked), and the efficiency of the expansion. [5] The efficiency is a measure of the losses due to friction, non-axial divergence as well as leakage in C-D nozzles. [6]
A rocket's required mass ratio as a function of effective exhaust velocity ratio. The classical rocket equation, or ideal rocket equation is a mathematical equation that describes the motion of vehicles that follow the basic principle of a rocket: a device that can apply acceleration to itself using thrust by expelling part of its mass with high velocity and can thereby move due to the ...
"In actual rocket nozzles, the exhaust velocity is not really uniform over the entire exit cross section and such velocity profiles are difficult to measure accurately. A uniform axial velocity, v e, is assumed for all calculations which employ one-dimensional problem descriptions. This effective exhaust velocity represents an average or mass ...
The proportionality constant varies, and can be solved for a uniform flow, where is the incoming air velocity, is the velocity at the actuator disc, and is the final exit velocity: d m d t = ρ A v {\displaystyle {\frac {\mathrm {d} m}{\mathrm {d} t}}=\rho A{v}}
For projectiles in unpowered flight, its velocity is highest at leaving the muzzle and drops off steadily because of air resistance.Projectiles traveling less than the speed of sound (about 340 m/s (1,100 ft/s) in dry air at sea level) are subsonic, while those traveling faster are supersonic and thus can travel a substantial distance and even hit a target before a nearby observer hears the ...