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Another issue is the number of colors in the image. Even images that were created as black on white drawings may end up with many shades of gray. Some line-drawing routines employ anti-aliasing; a pixel completely covered by the line will be black, but a pixel that is only partially covered will be gray.
Try to harmonize the sizes of images on a given page in order to maintain visual coherence. If "stacked" images in one section spill over into the next section at 1024×768 screen resolution, there may be too many images in that section.
High-resolution raster grids contain a large number of pixels, and thus consume a large amount of memory. This has led to multiple approaches to compressing the data volume into smaller files. The most common strategy is to look for patterns or trends in the pixel values, then store a parameterized form of the pattern instead of the original data.
Our "Cheatsheet" is a good starting point for learning basic Wikipedia formatting.A more complete guide is here.. You can take some formatting tips from the standard way Wikipedia articles are laid out.
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This minimal amount of information translates to a much smaller [13] file size compared to large raster images which are defined pixel by pixel. This said, a vector graphic with a small file size is often said to lack detail compared with a real-world photo. Correspondingly, one can infinitely zoom in on e.g., a circle arc, and it remains smooth.
The difference is that whilst D1 has a 4:3 aspect ratio 960H has a 16:9 widescreen aspect ratio. The extra pixels are used to form the increased area to the sides of the D1 image. The pixel density of 960H is identical to standard D1 resolution so it does not give any improvement in image quality, merely a wider aspect ratio.
If an alpha channel of the same size is added then there are 64 bits per pixel. Image editing software such as Adobe Photoshop started using 16 bits per channel fairly early in order to reduce the quantization on intermediate results (i.e. if an operation is divided by 4 and then multiplied by 4, it would lose the bottom 2 bits of 8-bit data ...