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log 10 of Hexane vapor pressure. Uses formula: log e P m m H g = {\displaystyle \scriptstyle \log _{e}P_{mmHg}=} log e ( 760 101.325 ) − 13.99935 log e ( T + 273.15 ) − 7284.572 T + 273.15 + 105.9605 + 1.410325 × 10 − 5 ( T + 273.15 ) 2 {\displaystyle \scriptstyle \log _{e}({\frac {760}{101.325}})-13.99935\log _{e}(T+273.15 ...
(760 mmHg = 101.325 kPa = 1.000 atm = normal pressure) This example shows a severe problem caused by using two different sets of coefficients. The described vapor pressure is not continuous—at the normal boiling point the two sets give different results. This causes severe problems for computational techniques which rely on a continuous vapor ...
Values are given in terms of temperature necessary to reach the specified pressure. Valid results within the quoted ranges from most equations are included in the table for comparison. A conversion factor is included into the original first coefficients of the equations to provide the pressure in pascals (CR2: 5.006, SMI: -0.875).
This is illustrated in the vapor pressure chart (see right) that shows graphs of the vapor pressures versus temperatures for a variety of liquids. [7] At the normal boiling point of a liquid, the vapor pressure is equal to the standard atmospheric pressure defined as 1 atmosphere, [ 1 ] 760 Torr, 101.325 kPa, or 14.69595 psi.
The following table lists the Van der Waals constants (from the Van der Waals equation) for a number of common gases and volatile liquids. [ 1 ] To convert from L 2 b a r / m o l 2 {\displaystyle \mathrm {L^{2}bar/mol^{2}} } to L 2 k P a / m o l 2 {\displaystyle \mathrm {L^{2}kPa/mol^{2}} } , multiply by 100.
Hexane (/ ˈ h ɛ k s eɪ n /) or n-hexane is an organic compound, a straight-chain alkane with six carbon atoms and the molecular formula C 6 H 14. [ 7 ] Hexane is a colorless liquid, odorless when pure, and with a boiling point of approximately 69 °C (156 °F).
Table data obtained from CRC Handbook of Chemistry and Physics 44th ed ... log of Benzene vapor pressure. Uses formula: ... for Benzene/n-Hexane [5] P = 760 mmHg BP ...
log 10 of Cyclohexane vapor pressure. Uses formula: log e P m m H g = {\displaystyle \scriptstyle \log _{e}P_{mmHg}=} log e ( 760 101.325 ) − 9.200978 log e ( T + 273.15 ) − 6354.898 T + 273.15 + 75.65058 + 7.374814 × 10 − 06 ( T + 273.15 ) 2 {\displaystyle \scriptstyle \log _{e}({\frac {760}{101.325}})-9.200978\log _{e}(T+ ...