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In elementary arithmetic, a carry is a digit that is transferred from one column of digits to another column of more significant digits. It is part of the standard algorithm to add numbers together by starting with the rightmost digits and working to the left. For example, when 6 and 7 are added to make 13, the "3" is written to the same column ...
For subtraction, subtract each pair of digits without borrow (borrow is a negative amount of carry), and then convert the numeral to standard form. For multiplication, multiply in the typical base-10 manner, without carry, then convert the numeral to standard form. For example, 2 + 3 = 10.01 + 100.01 = 110.02 = 110.1001 = 1000.1001
Adding two "1" digits produces a digit "0", while 1 must be added to the next column. This is similar to what happens in decimal when certain single-digit numbers are added together; if the result equals or exceeds the value of the radix (10), the digit to the left is incremented: 5 + 5 → 0, carry 1 (since 5 + 5 = 10 = 0 + (1 × 10 1))
The addition operation in all RBRs is carry-free, which means that the carry does not have to propagate through the full width of the addition unit. In effect, the addition in all RBRs is a constant-time operation. The addition will always take the same amount of time independently of the bit-width of the operands.
Example of addition with carry. The black numbers are the addends, the green number is the carry, and the blue number is the sum. In the rightmost digit, the addition of 9 and 7 is 16, carrying 1 into the next pair of the digit to the left, making its addition 1 + 5 + 2 = 8. Therefore, 59 + 27 = 86.
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5 + 5 → 0, carry 1 (since 5 + 5 = 10 = 0 + (1 × 10 1) ) 7 + 9 → 6, carry 1 (since 7 + 9 = 16 = 6 + (1 × 10 1) ) This is known as carrying. When the result of an addition exceeds the value of a digit, the procedure is to "carry" the excess amount divided by the radix (that is, 10/10) to the left, adding it to the next positional value.
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