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A white solid, it is the chloride salt of anilinium, which is the conjugate acid of aniline, C 6 H 5 NH 2. Anilinium chloride is produced by treatment of aniline with hydrochloric acid. The cation consists of a phenyl ring attached to a tetrahedral ammonium center. The C-N bond elongates from 1.41 Å in aniline to 1.474 Å in anilinium. [2]
Aniline (from Portuguese anil 'indigo shrub', and -ine indicating a derived substance) [6] is an organic compound with the formula C 6 H 5 NH 2. Consisting of a phenyl group ( −C 6 H 5 ) attached to an amino group ( −NH 2 ), aniline is the simplest aromatic amine .
Aniline absorbs in the K (220 - 250 nm) and the B (250 - 290 nm) bands exhibited by benzenoid compounds. The K and B bands arise from π to π* transitions as a result of the a group containing multiple bond being attached to the benzene ring. When dissolved in ethanol, λ max for aniline is 230 nm, but in dilute aqueous acid λ max is 203 nm ...
Substance Formula 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 60 °C 70 °C 80 °C 90 °C 100 °C Barium acetate: Ba(C 2 H 3 O 2) 2: 58.8: 62: 72: 75: 78.5: 77: 75
Other electrophiles are aromatic diazonium salts in diazonium couplings, carbon dioxide in the Kolbe–Schmitt reaction and activated carbonyl groups in the Pechmann condensation, hydroxycarbenium ion in the Blanc chloromethylation via an intermediate (hydroxymethyl)arene (benzyl alcohol), chloryl cation (ClO 3 +) for electrophilic perchlorylation.
The value gives an approximation for the content of aromatic compounds in the oil, [2] since the miscibility of aniline, which is also an aromatic compound suggests the presence of similar (i.e. aromatic) compounds in the oil. The lower the aniline point, the greater is the content of aromatic compounds in the oil.
The process has a high energy consumption, for example around 2,500 kWh (9,000 MJ) of electricity per tonne of sodium hydroxide produced. Because the process yields equivalent amounts of chlorine and sodium hydroxide (two moles of sodium hydroxide per mole of chlorine), it is necessary to find a use for these products in the same proportion ...
Me 3 CNH 2 + CHCl 3 + 3 NaOH → Me 3 CNC + 3 NaCl + 3 H 2 O. Similar reactions have been reported for aniline. It is used to prepare secondary amines. Test for ...