Search results
Results from the WOW.Com Content Network
Chloroform, [10] or trichloromethane (often abbreviated as TCM), is an organochloride with the formula C H Cl 3 and a common solvent.It is a volatile, colorless, sweet-smelling, dense liquid produced on a large scale as a precursor to refrigerants and PTFE. [11]
In 1835, the French chemist Auguste Laurent recognised chloroform as CCl 2 • HCl (then written as C 8 Cl 8 • H 4 Cl 4) [a] in his paper on analysing some organohalides. Laurent also predicted a compound seemingly consisting of 2 parts dichlorocarbene which he named Chlorétherose (possibly Tetrachloroethylene, which was not known to exist at the time.) [8]
Me 3 CNH 2 + CHCl 3 + 3 NaOH → Me 3 CNC + 3 NaCl + 3 H 2 O. Similar reactions have been reported for aniline. It is used to prepare secondary amines.
Me 3 CNH 2 + CHCl 3 + 3 NaOH → Me 3 CNC + 3 NaCl + 3 H 2 O. ... For example, benzyl isocyanide has a pK a of 27.4. In comparison, benzyl cyanide has a pK a of 21.9 ...
In chemistry, the haloform reaction (also referred to as the Lieben haloform reaction) is a chemical reaction in which a haloform (CHX 3, where X is a halogen) is produced by the exhaustive halogenation of an acetyl group (R−C(=O)CH 3, where R can be either a hydrogen atom, an alkyl or an aryl group), in the presence of a base.
Chloroform (1) is deprotonated by a strong base (normally hydroxide) to form the chloroform carbanion (2) which will quickly alpha-eliminate to give dichlorocarbene (3); this is the principal reactive species. The hydroxide will also deprotonate the phenol (4) to give a negatively charged phenoxide (5). The negative charge is delocalised into ...
Sodium hydroxide – NaOH; Sodium hypobromite – NaOBr; Sodium hypochlorite – NaOCl; Sodium hypoiodite – NaOI; Sodium hypophosphite – NaPO 2 H 2; Sodium iodate – NaIO 3; Sodium iodide – NaI; Sodium manganate – Na 2 MnO 4; Sodium molybdate – Na 2 MoO 4; Sodium monofluorophosphate (MFP) – Na 2 PFO 3; Sodium nitrate – NaNO 3 ...
An example in scheme 2 is the reaction of tert-butylbromide with potassium ethoxide in ethanol. E1 eliminations happen with highly substituted alkyl halides for two main reasons. Highly substituted alkyl halides are bulky, limiting the room for the E2 one-step mechanism; therefore, the two-step E1 mechanism is favored.