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  2. Earth's orbit - Wikipedia

    en.wikipedia.org/wiki/Earth's_orbit

    One complete orbit takes 365.256 days (1 sidereal year), during which time Earth has traveled 940 million km (584 million mi). [2] Ignoring the influence of other Solar System bodies, Earth's orbit, also called Earth's revolution, is an ellipse with the Earth–Sun barycenter as one focus with a current eccentricity of 0.0167. Since this value ...

  3. Orbital period - Wikipedia

    en.wikipedia.org/wiki/Orbital_period

    This corresponds to 1 ⁄ √2 times (≈ 0.707 times) the escape velocity. ... a small body in circular orbit 10.5 cm ... owing to the motion of Earth around the Sun.

  4. Free-fall time - Wikipedia

    en.wikipedia.org/wiki/Free-fall_time

    The free-fall time is the characteristic time that would take ... the orbit of the Earth around the Sun with ... 35 minutes for a body of mean density 1 g/cm 3.

  5. Newcomb's Tables of the Sun - Wikipedia

    en.wikipedia.org/wiki/Newcomb's_Tables_of_the_Sun

    The bulk of the work, however, is a collection of tabulated precomputed values that provide the position of the sun at any point in time. Newcomb's Tables were the basis for practically all ephemerides of the Sun published from 1900 through 1983, including the annual almanacs of the U.S. Naval Observatory and the Royal Greenwich Observatory.

  6. Earth - Wikipedia

    en.wikipedia.org/wiki/Earth

    Earth's rotational velocity also varies in a phenomenon known as length-of-day variation. [171] Earth's annual orbit is elliptical rather than circular, and its closest approach to the Sun is called perihelion. In modern times, Earth's perihelion occurs around 3 January, and its aphelion around 4 July.

  7. Kepler's laws of planetary motion - Wikipedia

    en.wikipedia.org/wiki/Kepler's_laws_of_planetary...

    Since velocity is inverse to time, the distance from the sun would be proportional to the time to cover a small piece of the orbit. This is approximately true for elliptical orbits. The area swept out is proportional to the overall time. This is also approximately true.

  8. Sun-synchronous orbit - Wikipedia

    en.wikipedia.org/wiki/Sun-synchronous_orbit

    An orbit will be Sun-synchronous when the precession rate ρ = ⁠ dΩ / dt ⁠ equals the mean motion of the Earth about the Sun n E, which is 360° per sidereal year (1.990 968 71 × 10 −7 rad/s), so we must set n E = ⁠ ΔΩ E / T E ⁠ = ρ = ⁠ ΔΩ / T ⁠, where T E is the Earth orbital period, while T is the period of the spacecraft ...

  9. Ecliptic - Wikipedia

    en.wikipedia.org/wiki/Ecliptic

    For example, the Sun is north of the celestial equator for about 185 days of each year, and south of it for about 180 days. [7] The variation of orbital speed accounts for part of the equation of time. [8] Because of the movement of Earth around the Earth–Moon center of mass, the apparent path of the Sun wobbles slightly, with a period of ...