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If 2 k + 1 is prime and k > 0, then k itself must be a power of 2, [1] so 2 k + 1 is a Fermat number; such primes are called Fermat primes. As of 2023 [update] , the only known Fermat primes are F 0 = 3 , F 1 = 5 , F 2 = 17 , F 3 = 257 , and F 4 = 65537 (sequence A019434 in the OEIS ).
The limit of a sequence of powers of a number greater than one diverges; in other words, the sequence grows without bound: b n → ∞ as n → ∞ when b > 1. This can be read as "b to the power of n tends to +∞ as n tends to infinity when b is greater than one". Powers of a number with absolute value less than one tend to zero: b n → 0 as ...
For if every even number greater than 4 is the sum of two odd primes, adding 3 to each even number greater than 4 will produce the odd numbers greater than 7 (and 7 itself is equal to 2+2+3). In 2013, Harald Helfgott released a proof of Goldbach's weak conjecture. [ 2 ]
A prime number is a number greater than 1 that can only be divided by… Answer: One and itself. What is the sum of the interior angles of a triangle? Answer: 180 degrees. What is the square root ...
G(3) is at least 4 (since cubes are congruent to 0, 1 or −1 mod 9); for numbers less than 1.3 × 10 9, 1 290 740 is the last to require 6 cubes, and the number of numbers between N and 2N requiring 5 cubes drops off with increasing N at sufficient speed to have people believe that G(3) = 4; [22] the largest number now known not to be a sum of ...
The only known powers of 2 with all digits even are 2 1 = 2, 2 2 = 4, 2 3 = 8, 2 6 = 64 and 2 11 = 2048. [12] The first 3 powers of 2 with all but last digit odd is 2 4 = 16, 2 5 = 32 and 2 9 = 512. The next such power of 2 of form 2 n should have n of at least 6 digits.
Then, f(x)g(x) = 4x 2 + 4x + 1 = 1. Thus deg( f ⋅ g ) = 0 which is not greater than the degrees of f and g (which each had degree 1). Since the norm function is not defined for the zero element of the ring, we consider the degree of the polynomial f ( x ) = 0 to also be undefined so that it follows the rules of a norm in a Euclidean domain.
Repeat the procedure, since the number is greater than 7. Now, 4 becomes 5, which must be added to 6. That is 11. Repeat the procedure one more time: 1 becomes 3, which is added to the second digit (1): 3 + 1 = 4. Now we have a number smaller than 7, and this number (4) is the remainder of dividing 186/7.