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Its symbol is written in several forms as m/s 2, m·s −2 or ms −2, , or less commonly, as (m/s)/s. [1] As acceleration, the unit is interpreted physically as change in velocity or speed per time interval, i.e. metre per second per second and is treated as a vector quantity.
During the first 0.05 s the ball drops one unit of distance (about 12 mm), by 0.10 s it has dropped at total of 4 units, by 0.15 s 9 units, and so on. Near the surface of the Earth, the acceleration due to gravity g = 9.807 m/s 2 ( metres per second squared , which might be thought of as "metres per second, per second"; or 32.18 ft/s 2 as "feet ...
At a fixed point on the surface, the magnitude of Earth's gravity results from combined effect of gravitation and the centrifugal force from Earth's rotation. [ 2 ] [ 3 ] At different points on Earth's surface, the free fall acceleration ranges from 9.764 to 9.834 m/s 2 (32.03 to 32.26 ft/s 2 ), [ 4 ] depending on altitude , latitude , and ...
In classical mechanics, for a body with constant mass, the (vector) acceleration of the body's center of mass is proportional to the net force vector (i.e. sum of all forces) acting on it (Newton's second law): = =, where F is the net force acting on the body, m is the mass of the body, and a is the center-of-mass acceleration.
kn/s ≡ 1 kn/s ≈ 5.1 4 × 10 −1 m/s 2: metre per second squared (SI unit) m/s 2: ≡ 1 m/s 2 = 1 m/s 2: mile per hour per second: mph/s ≡ 1 mi/(h⋅s) = 4.4704 × 10 −1 m/s 2: mile per minute per second: mpm/s ≡ 1 mi/(min⋅s) = 26.8224 m/s 2: mile per second squared: mps 2: ≡ 1 mi/s 2 = 1.609 344 × 10 3 m/s 2: standard gravity: g ...
Near Earth's surface, the acceleration due to gravity, accurate to 2 significant figures, is 9.8 m/s 2 (32 ft/s 2). This means that, ignoring the effects of air resistance , the speed of an object falling freely will increase by about 9.8 metres per second (32 ft/s) every second.
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Near the surface of the Earth, an object in free fall in a vacuum will accelerate at approximately 9.8 m/s 2, independent of its mass. With air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (190 km/h or 118 mph [4]) for a human skydiver.