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Learn how to use mole ratios as conversion factors in stoichiometry calculations and how to find experimental molar ratios from reaction data. See examples, video, and practice problems with answers.
Mole percent is the percentage of moles of a component in a mixture, calculated by dividing the moles by the total moles and multiplying by 100. Learn how to use mole fraction and mole percent to solve problems with solutions of sodium chloride and water.
Learn how to convert volume to moles for pure liquids, solids and solutions using density and molarity. See examples, formulas and video explanations.
Learn the formula to find the number of moles of a substance in a solution from its molarity and volume. See an example problem with NaCl and the solution steps.
Learn how to convert between moles and grams, moles and liters, and moles and particles using molar mass, molar volume, and Avogadro's number. See examples and definitions of mole and other units of substance.
Learn how to use the Ideal Gas Law to find the volume of 1 mole of a gas at Standard Temperature and Pressure (STP), which is 22.41 L. See the equation, the units, and the answer with steps on Socratic.
You multiply the molarity by the number of osmoles that each solute produces. > An osmole (Osmol) is 1 mol of particles that contribute to the osmotic pressure of a solution. For example, "NaCl" dissociates completely in water to form "Na"^+ ions and "Cl"^"-" ions. Thus, each mole of "NaCl" becomes two osmoles in solution: one mole of "Na"^+ and one mole of "Cl"^"-". A solution of 1 mol/L ...
answer below First, you need to know Avogadro's number, which is directly associated with molarity. The number is: 6.02*10^23 Now, one mole = 6.02*10^23 particles So, multiply the # of moles you have by Avogadro's number, and you have your answer
Here's one way to do it. > Example Concentrated hydrochloric acid is usually available at a concentration of 37.7% by mass. The density of the solution is 1.19 g/mL. What is its molar concentration? Solution Step 1. Calculate the mass of 1 L of solution. "Mass of solution" = 1000 color(red)(cancel(color(black)("mL soln"))) × "1.19 g soln" /(1color(red)(cancel(color(black)("mL soln ...
"0.910 moles Na"^(+) You're dealing with a soluble ionic compound, so you know for a fact that it dissociates completely in aqueous solution to produce cations, which are positively charged ions, and anions, which are negatively charged ions. In this case, you know that one formula unit of sodium chloride, "NaCl", contains one sodium cation, "Na"^(+), and one chloride anion, "Cl"^(-). This ...