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2. List of prime numbers - Wikipedia

   en.wikipedia.org/wiki/List_of_prime_numbers

   This is a list of articles about prime numbers. A prime number (or prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself. By Euclid's theorem, there are an infinite number of prime numbers. Subsets of the prime numbers may be generated with various formulas for primes.

3. Table of prime factors - Wikipedia

   en.wikipedia.org/wiki/Table_of_prime_factors

   An economical number has been defined as a frugal number, but also as a number that is either frugal or equidigital. gcd( m , n ) ( greatest common divisor of m and n ) is the product of all prime factors which are both in m and n (with the smallest multiplicity for m and n ).

4. List of numbers - Wikipedia, the free encyclopedia

   en.wikipedia.org/wiki/List_of_numbers

   A list of articles about numbers (not about numerals). Topics include powers of ten, notable integers, prime and cardinal numbers, and the myriad system.

5. Squared triangular number - Wikipedia

   en.wikipedia.org/wiki/Squared_triangular_number

   A square whose side length is a triangular number can be partitioned into squares and half-squares whose areas add to cubes. From Gulley (2010).The nth coloured region shows n squares of dimension n by n (the rectangle is 1 evenly divided square), hence the area of the nth region is n times n x n.

6. Aaron Rodgers Is ‘a Very Difficult Person to Understand ...

   www.aol.com/aaron-rodgers-very-difficult-person...

   PEOPLE spoke with the directors behind Netflix's new docuseries 'Aaron Rodgers: Enigma,' which began streaming Tuesday

7. Centered cube number - Wikipedia

   en.wikipedia.org/wiki/Centered_cube_number

   Because of the factorization (2n + 1)(n 2 + n + 1), it is impossible for a centered cube number to be a prime number. [3] The only centered cube numbers which are also the square numbers are 1 and 9, [4] [5] which can be shown by solving x 2 = y 3 + 3y, the only integer solutions being (x,y) from {(0,0), (1,2), (3,6), (12,42)}, By substituting a=(x-1)/2 and b=y/2, we obtain x^2=2y^3+3y^2+3y+1.