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  2. Area of a triangle - Wikipedia

    en.wikipedia.org/wiki/Area_of_a_triangle

    The area of a triangle can be demonstrated, for example by means of the congruence of triangles, as half of the area of a parallelogram that has the same base length and height. A graphic derivation of the formula T = h 2 b {\displaystyle T={\frac {h}{2}}b} that avoids the usual procedure of doubling the area of the triangle and then halving it.

  3. Equilateral triangle - Wikipedia

    en.wikipedia.org/wiki/Equilateral_triangle

    In general, the area of a triangle is half the product of its base and height. The formula of the area of an equilateral triangle can be obtained by substituting the altitude formula. [7] Another way to prove the area of an equilateral triangle is by using the trigonometric function. The area of a triangle is formulated as the half product of ...

  4. Triangle - Wikipedia

    en.wikipedia.org/wiki/Triangle

    An example of a circular triangle with three convex edges is a Reuleaux triangle, which can be made by intersecting three circles of equal size. The construction may be performed with a compass alone without needing a straightedge, by the Mohr–Mascheroni theorem. Alternatively, it can be constructed by rounding the sides of an equilateral ...

  5. Isosceles triangle - Wikipedia

    en.wikipedia.org/wiki/Isosceles_triangle

    The same area formula can also be derived from Heron's formula for the area of a triangle from its three sides. However, applying Heron's formula directly can be numerically unstable for isosceles triangles with very sharp angles, because of the near-cancellation between the semiperimeter and side length in those triangles. [20]

  6. Napoleon's theorem - Wikipedia

    en.wikipedia.org/wiki/Napoleon's_theorem

    Napoleon's theorem: If the triangles centered on L, M, N are equilateral, then so is the green triangle.. In geometry, Napoleon's theorem states that if equilateral triangles are constructed on the sides of any triangle, either all outward or all inward, the lines connecting the centres of those equilateral triangles themselves form an equilateral triangle.

  7. Triangle center - Wikipedia

    en.wikipedia.org/wiki/Triangle_center

    Let A'BC be the equilateral triangle having base BC and vertex A' on the negative side of BC and let AB'C and ABC' be similarly constructed equilateral triangles based on the other two sides of triangle ABC. Then the lines AA', BB', CC' are concurrent and the point of concurrence is the 1st isogonal center. Its trilinear coordinates are

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  9. Incircle and excircles - Wikipedia

    en.wikipedia.org/wiki/Incircle_and_excircles

    The ratio of the area of the incircle to the area of the triangle is less than or equal to /, with equality holding only for equilateral triangles. [ 19 ] Suppose A B C {\displaystyle \triangle ABC} has an incircle with radius r {\displaystyle r} and center I {\displaystyle I} .

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