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Conversely, a current source provides a constant current, as long as the impedance of the load is sufficiently lower than the current source's parallel impedance (which is preferably very high and ideally infinite). In the case of transistor current sources, impedances of a few megohms (at low frequencies) are typical. Because power is current ...
Under a constant-current discharge at 100mA, energy extracted from the battery is proportional to the area under the graph: energy extracted before reaching a 1.3V cutoff additional energy extracted before reaching a 1.1V cutoff
The sum of all areas (multiplied by the current of 100mA) is the total energy extractable from the cell by constant-current discharge. Note: as the voltage and current are measured externally, the energy calculated in this way is explicitly work done in the load, that is, electrical work that the battery can do.
Load regulation of a constant-voltage source is defined by the equation: [3] % = % Where: is the voltage at maximum load. The maximum load is the one that draws the greatest current, i.e. the lowest specified load resistance (never short circuit);
Every time an electrical power device (for example: heaters, lamps, motors, transformers or similar power loads) turns on or off, its switch, relay or contactor transitions either from a CLOSED to an OPEN state ("BREAK") or from an OPEN to a CLOSED state ("MAKE"), under load, an electrical arc occurs between the two contact points (electrodes) of the switch.
In electronics, a constant current system is one that varies the voltage across a load to maintain a constant electric current.When a component is indicated to be driven by a constant current, the driver circuit is, in essence, a current regulator and must appear to the component as a current source of suitable reliability.
Without a heat sink at an ambient temperature at 50 °C, a maximum power dissipation of (T J-T A)/R θJA = ((125-50)/80) = 0.98 W can be permitted.. In a constant voltage mode with an input voltage source at V IN at 34 V and a desired output voltage of 5 V, the maximum output current will be P MAX / (V IN-V O) = 0.98 / (34-5) = 32 mA.
This page was last edited on 1 December 2005, at 20:53 (UTC).; Text is available under the Creative Commons Attribution-ShareAlike 4.0 License; additional terms may apply.
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