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1/2 We have: sqrt(1/4) Using a simple observation, we got: =sqrt((1^2)/(2^2)) Using the properties, (a^b)/(c^b)=(a/c)^b. So, we got =sqrt((1/2)^2) =+-1/2 Since we are talking about real numbers, we will only take the principal (positive) square root, and so the answer will be just 1/2.
2 and -2 are square roots of 4. The principal square root of 4, (denoted sqrt4) is 2 A number is a square root of 4 is, when multiplied by itself, the result is 4. In notation: n is a square root of 4 if n^2 = n xx n = 4 There are two numbers that will work 2 xx 2 = 4 and also -2 xx -2 = 4 so the numbers 2 and -2 are square roots of 4. When people talk about the square root of 4, they usually ...
There are two common ways to simplify radical expressions, depending on the denominator. Using the identities #\sqrt{a}^2=a# and #(a-b)(a+b)=a^2-b^2#, in fact, you can get rid of the roots at the denominator.
-4 has two complex square roots, namely +-2i (where i = sqrt(-1)) ... What is the square root of negative 4?
The square roots of 4 are: sqrt(4) = 2 -sqrt(4) = -2 Every positive real number n has exactly two real square roots. The one we call the principal square root and denote as sqrt(n) is the positive one. The other square root is -sqrt(n), since: (-sqrt(n))^2 = (sqrt(n))^2 = n In the case of 4, we find 2^2 = 4. So the principal square root of 4 is 2.
Now, let's explore how to translate a square root function vertically. y = #sqrt(x) + 3# or y = #sqrt(x) - 4#. The addition or subtraction on the OUTSIDE of the square root function will cause the graph to translate up or down. Adding 3 will raise the graph up, and subtracting 4 will lower the graph by 4 units. (see graph)
There seem to me to be two aspects to this question: (1) What does "square root of x^2+4" mean? sqrt(x^2+4) is a term which when squared yields x^2+4 : sqrt(x^2+4) xx sqrt(x^2+4) = x^2 + 4 In other words t = sqrt(x^2+4) is the solution t of the equation t^2 = x^2+4 (2) Can the formula sqrt(x^2+4) be simplified? No. For starters (x^2+4) > 0 for all x in RR, so it has no linear factors with real ...
Given: #(sqrt(4+h)-2)/h# We find: #(sqrt(4+h)-2)/h = ((sqrt(4+h)-2)(sqrt(4+h)+2))/(h(sqrt(4+h)+2))# #color(white)((sqrt(4+h)-2)/h) = ((4+h)-4)/(h(sqrt(4+h)+2))#
Find the square root of 4-3i? Precalculus. 2 Answers Vinícius Ferraz Aug 7, 2018 ...
The square root equals #x+2#. Explanation: First, factor the expression under the radical: