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Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object. (Velocity is on the y-axis and time on the x-axis. Multiplying the velocity by the time, the time cancels out, and only displacement remains.)
English: Graph of the velocity versus time of a skydiver reaching terminal velocity. The time evolution is given by = ...
Intuitively, the velocity increases linearly, so the average velocity multiplied by time is the distance traveled while increasing the velocity from v 0 to v, as can be illustrated graphically by plotting velocity against time as a straight line graph. Algebraically, it follows from solving [1] for
Date/Time Thumbnail Dimensions User Comment; current: 01:22, 25 February 2007: 496 × 504 (111 KB) Stannered {{Information |Description=Example of a en:velocity vs. time graph, and the relationship between velocity v, en:displacement s, and en:acceleration a. Traced in en:Inkscape from an original drawn in en:Microsoft Paint. |Source=[[:
File:Velocity Time physics graph.jpg: Licensing. This file is licensed under the Creative Commons Attribution-Share Alike 4.0 International license. You are free:
In terms of a displacement-time (x vs. t) graph, the instantaneous velocity (or, simply, velocity) can be thought of as the slope of the tangent line to the curve at any point, and the average velocity as the slope of the secant line between two points with t coordinates equal to the boundaries of the time period for the average velocity.
Many other fundamental quantities in science are time derivatives of one another: force is the time derivative of momentum; power is the time derivative of energy; electric current is the time derivative of electric charge; and so on. A common occurrence in physics is the time derivative of a vector, such as velocity or displacement. In dealing ...
which illustrates the kinetic energy is in general a function of the generalized velocities, coordinates, and time if the constraints also vary with time, so T = T(q, dq/dt, t). In the case the constraints on the particles are time-independent, then all partial derivatives with respect to time are zero, and the kinetic energy is a homogeneous ...
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