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A certain amount of univalent ions provides the same amount of equivalents while the same amount of divalent ions provides twice the amount of equivalents. For example, 1 mmol (0.001 mol) of Na + is equal to 1 meq, while 1 mmol of Ca 2+ is equal to 2 meq.
BUN is an indication of kidney health. The normal range is 2.1–7.1 mmol/L or 6–20 mg/dL. [1]The main causes of an increase in BUN are: high-protein diet, decrease in glomerular filtration rate (GFR) (suggestive of kidney failure), decrease in blood volume (hypovolemia), congestive heart failure, gastrointestinal hemorrhage, [5] fever, rapid cell destruction from infections, athletic ...
= 205.196 548 3 mg carat (metric) ct ≡ 200 mg = 200 mg clove: ≡ 8 lb av = 3.628 738 96 kg: crith: ≡ mass of 1 L of hydrogen gas at STP: ≈ 89.9349 mg dalton: Da 1/12 the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state and at rest: ≈ 1.660 539 068 92 (52) × 10 −27 kg [20] dram (apothecary ...
Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. [1] For use in broader applications, it is defined as amount of substance of solute per unit volume of solution, or per unit volume available to the species, represented by lowercase : [2]
Unit conversion formula from mmol/L to mg/dL [5] m g / d L = m m o l / L × m o l e c u l a r w e i g h t ÷ 10 {\displaystyle mg/dL=mmol/L\times molecular\ weight\div 10} Since the molecular mass of glucose C 6 H 12 O 6 is 180.156 g/mol, the factor between the two units is about 18, so 1 mmol/L of glucose is equivalent to 18 mg/dL.
V eq is the volume of titrant (ml) consumed by the crude oil sample and 1 ml of spiking solution at the equivalent point, b eq is the volume of titrant (ml) consumed by 1 ml of spiking solution at the equivalent point, 56.1 g/mol is the molecular weight of KOH, W oil is the mass of the sample in grams. The normality (N) of titrant is calculated as:
In chemistry, equivalent weight (also known as gram equivalent [1] or equivalent mass) is the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance.
The osmol gap is typically calculated with the following formula (all values in mmol/L): = = ([+] + [] + []) In non-SI laboratory units: Calculated osmolality = 2 x [Na mmol/L] + [glucose mg/dL] / 18 + [BUN mg/dL] / 2.8 + [ethanol/3.7] [3] (note: the values 18 and 2.8 convert mg/dL into mmol/L; the molecular weight of ethanol is 46, but empiric data shows that it does not act as an ideal ...