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The slope in the given equation is 3. The y-intercept of the given equation is −7. Count down 7 units on the y-axis and put your first point. The count up 3 units and over 1 unit. graph {3x-7 [-10, 10, -5, 5]} The equation is already in slope-intercept form: y=mx+b Where m is the slope and b is the intercept. The slope in the given equation is 3.
reajulia3. report flag outlined. Answer: up 7, down 3 and right 1. Step-by-step explanation: You go on the map and put a dot at 7 which is up 7. then you go to the down 3 and to the right 1 and there is your answer. arrow right. Explore similar answers. messages.
Where 'a' is the x-intercept of the line and ‘b’ is the y-intercept of the line. The equation of the line is given below. y = -3x + 7. Convert the line into intercepts form, then we have. y = - 3x + 7. 3x + y = 7. x / (7/3) + y / 7 = 1. The equation of the line is drawn below. More about the linear equation link is given below.
Following the steps of sketching the graph of (y = 3x +7) it can be conclude that the graph of (y = 3x +7) intersect x-axis at (x = 3) and y - axis at (y = 7). So, the correct option is c). Given : The steps for sketching the graph of the function (y = 3x + 7) are as follows: Step 1 - Draw the graph of (y = x).
to check the solution: substitute 2 for x in both equations. y = 3(2) −7. y = − 1. y = − (2) +1. y = − 1. (2,-1) is the solution for system y = 3x − 7 and y = − x + 1. Answer link. (2,-1) graph both equations on the same graph. red graph is y=3x-7 blue graph is y=-x+1 the point of intersect is (2, -1) to check the solution ...
Refer to the explanation below. y - 7= -3x First begin by rearranging the equation to form a linear function. y - 7= -3x y = -3x + 7 Now, looking at the equation you can see that: the gradient is negative due to the -3 the graph has been shifted up by 7 Now, find the point of intersection of the graph along the y-axis by making x = 0. y = -3x + 7 y = -3(0) + 7 y = 0 + 7 y = 7 Therefore, (0,7 ...
How do you graph #y=3x+7# using intercepts? ... How do you use the x and y intercepts to graph a linear ...
y = 3 ×02 = 0. Given that x is zero when y is zero this mat be shown as: (x,y) → (0,0) This is called an ordered pair and this case is the 'vertex'. As the line of symmetry passes through the vertex then this particular graph is symmetrical about the y-axis. As 3x2 is positive the shape is that of ∪.
The y-intercept is (0,-7). y=3x-7 The x-intercept is the value for x when y=0. Substitute 0 for y. 0=3x-7 Subtract 3x from both sides. -3x=-7 Divide both sides by -3. x=-7/3 The y-intercept is the value of y when x=0. Substitute 0 for x. y=3(0)-7 y=-7 The x-intercept is (-7/3,0). The y-intercept is (0,-7) graph{y=3x-7 [-11.05, 10.715, -8.21, 2. ...
Multiply both sides by −1: y = 3x − 7. This means that the line has a gradient (slope) of 3, and a y-intercept of −7. Plot the points (3.3,0) ; (0,-7) Join these two points you will get the curve. Given - 3x-y=7 Find the two intercepts. Plot them and join them with a straight line. x-intercept At y=0 3x-0=7 x=7/3=3.3 (3.3,0) y-intercept ...