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  2. What would happen without a Leap Day? More than you ... - AOL

    www.aol.com/news/happen-without-leap-day-more...

    Later, on a calendar yet to come (we'll get to it), it was decreed that years divisible by 100 not follow the four-year leap day rule un ... 1800 and 1900, but 2000 had one. In the next 500 years ...

  3. Divisibility rule - Wikipedia

    en.wikipedia.org/wiki/Divisibility_rule

    Add the last digit to twice the rest. The result must be divisible by 8. 56: (5 × 2) + 6 = 16. The last three digits are divisible by 8. [2] [3] 34,152: examine divisibility of just 152: 19 × 8. The sum of the ones digit, double the tens digit, and four times the hundreds digit is divisible by 8. 34,152: 4 × 1 + 5 × 2 + 2 = 16. 9

  4. International Fixed Calendar - Wikipedia

    en.wikipedia.org/wiki/International_Fixed_Calendar

    There is a leap year in every year whose number is divisible by 4, but not if the year number is divisible by 100, unless it is also divisible by 400. So although the year 2000 was a leap year, the years 1700, 1800, and 1900 were common years.

  5. Leap year - Wikipedia

    en.wikipedia.org/wiki/Leap_year

    Every year that is exactly divisible by four is a leap year, except for years that are exactly divisible by 100, but these centurial years are leap years if they are exactly divisible by 400. For example, the years 1700, 1800, and 1900 are not leap years, but the years 1600 and 2000 are. [8] 1800 calendar, showing that February had only 28 days

  6. February 29 - Wikipedia

    en.wikipedia.org/wiki/February_29

    In the Gregorian calendar, the standard civil calendar used in most of the world, February 29 is added in each year that is an integer multiple of four, unless it is evenly divisible by 100 but not by 400. For example, 1900 was not a leap year, but 2000 was.

  7. Table of divisors - Wikipedia

    en.wikipedia.org/wiki/Table_of_divisors

    d() is the number of positive divisors of n, including 1 and n itself; σ() is the sum of the positive divisors of n, including 1 and n itselfs() is the sum of the proper divisors of n, including 1 but not n itself; that is, s(n) = σ(n) − n

  8. Year 2000 problem - Wikipedia

    en.wikipedia.org/wiki/Year_2000_problem

    This method works fine for the year 2000 (because it is a leap year), and will not become a problem until 2100, when older legacy programs will likely have long since been replaced. Other programs contained incorrect leap year logic, assuming for instance that no year divisible by 100 could be a leap year.

  9. Century leap year - Wikipedia

    en.wikipedia.org/wiki/Century_leap_year

    This eliminates 3 of the 4 end-of-century years in a 400-year period. For example, the years 1600, 2000, 2400, and 2800 are century leap years since those numbers are evenly divisible by 400, while 1700, 1800, 1900, 2100, 2200, 2300, 2500, 2600, 2700, 2900, and 3000 are common years despite being evenly divisible by 4. This scheme brings the ...